如何将Groovy列表强制转换为对象？

发布时间：2020-12-14 16:24:08 所属栏目：大数据来源：网络整理

导读：我正在关注使用列表和地图作为构造函数的 this博文. 为什么以下列表无法强制反对？ class Test { static class TestObject { private int a = 1; protected int b = 2; public int c = 3; int d = 4; String s = "s"; } static main(args) { def obj = [1,2,

我正在关注使用列表和地图作为构造函数的 this博文.

为什么以下列表无法强制反对？

class Test {
    static class TestObject {
        private int a = 1;
        protected int b = 2;
        public int c = 3;
        int d = 4;
        String s = "s";
    }

    static main(args) {
        def obj = [1,2,3,4,'s'] as TestObject
    }
}

我得到这个例外：

Caught: org.codehaus.groovy.runtime.typehandling.GroovyCastException: Cannot cast object '[1,s]' with class 'java.util.ArrayList' to class 'in.ksharma.Test$TestObject' due to: groovy.lang.GroovyRuntimeException: Could not find matching constructor for: in.ksharma.Test$TestObject(java.lang.Integer,java.lang.Integer,java.lang.String)
org.codehaus.groovy.runtime.typehandling.GroovyCastException: Cannot cast object '[1,java.lang.String)
    at in.ksharma.Test.main(Test.groovy:22)

解决方法

你可以使用map：

class Test {
    static class TestObject {
        private int a = 1;
        protected int b = 2;
        public int c = 3;
        int d = 4;
        String s = "s";
    }

    static main(args) {
        def o = ['a':1,b:'2',c:'3','d':5,s:'s'] as TestObject
        println o.d
    }
}

马上就会考虑清单.

编辑

嗯..我不确定列表是否可行.仅当您添加适当的构造函数时.
完整样本：

class Test {
    static class TestObject {
        TestObject() {
        }

        TestObject(a,b,c,d,s) {
            this.a = a
            this.b = b
            this.c = c
            this.d = d
            this.s = s
        }


        private int a = 1;
        protected int b = 2;
        public int c = 3;
        int d = 4;
        String s = "s";
    }

    static main(args) {
        def obj = ['a':1,s:'s'] as TestObject
        assert obj.d == 5
        obj = [1,6,'s'] as TestObject
        assert obj.d == 6
    }
}

（编辑：李大同）

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