Leetcode 105
发布时间:2020-12-14 05:13:36 所属栏目:大数据 来源:网络整理
导读:/* * * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x),left(NULL),right(NULL) {} * }; */ class Solution { public : TreeNode * buildTree(vector int preorder,v
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x),left(NULL),right(NULL) {} * }; */ class Solution { public: TreeNode* buildTree(vector<int>& preorder,vector<int>& inorder) { return DFS(preorder,0,inorder,inorder.size()-1); } TreeNode* DFS(vector<int> preorder,int pos,vector<int> inorder,int ileft,int iright){ if(ileft > iright) return NULL; int i=0; for(i=ileft;i <= iright;i++){ if(preorder[pos] == inorder[i])break; } TreeNode* cur = new TreeNode(preorder[pos]); cur->left = DFS(preorder,pos+1,ileft,i-1); cur->right = DFS(preorder,pos+i-ileft+1,i+1,iright); return cur; } }; (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |