codetest
发布时间:2020-12-14 04:46:41 所属栏目:大数据 来源:网络整理
导读:测试代码表现 1 def depth_of_tree(tree): #This is the recursive function to find the depth of binary tree. 2 if tree is None: 3 return 0 4 else : 5 depth_l_tree = depth_of_tree(tree.left) 6 depth_r_tree = depth_of_tree(tree.right) 7 if dept
测试代码表现1 def depth_of_tree(tree): #This is the recursive function to find the depth of binary tree. 2 if tree is None: 3 return 0 4 else: 5 depth_l_tree = depth_of_tree(tree.left) 6 depth_r_tree = depth_of_tree(tree.right) 7 if depth_l_tree > depth_r_tree: 8 return 1 + depth_l_tree 9 10 return 1 + depth_r_tree 11 12 13 def is_full_binary_tree(tree): # This functions returns that is it full binary tree or not? 14 15 return True 16 if (tree.left is None) and (tree.right is None): 17 18 if (tree.left is not None) and (tree.right is not None): 19 return (is_full_binary_tree(tree.left) and is_full_binary_tree(tree.right)) 20 21 return False def depth_of_tree(tree): #This is the recursive function to find the depth of binary tree. if tree is None: return 0 else: depth_l_tree = depth_of_tree(tree.left) depth_r_tree = depth_of_tree(tree.right) if depth_l_tree > depth_r_tree: return 1 + depth_l_tree else: return 1 + depth_r_tree def is_full_binary_tree(tree): # This functions returns that is it full binary tree or not? if tree is None: return True if (tree.left is None) and (tree.right is None): return True if (tree.left is not None) and (tree.right is not None): return (is_full_binary_tree(tree.left) and is_full_binary_tree(tree.right)) else: return False (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |