LC 898. Bitwise ORs of Subarrays
发布时间:2020-12-14 04:25:53 所属栏目:大数据 来源:网络整理
导读:? ? We have an array? A ?of non-negative integers. For every (contiguous) subarray? B =?[A[i],A[i+1],...,A[j]] ?(with? i = j ),we take the bitwise OR of all the elements in? B ,obtaining a result? A[i] | A[i+1] | ... | A[j] . Return the nu
? ? We have an array? For every (contiguous) subarray? Return the number of possible?results.? (Results that occur more than once are only counted once in the final answer.)
Runtime:?652 ms
Memory Usage:?49.7 MB
class Solution { public: int subarrayBitwiSEORs(vector<int>& A) { unordered_set<int> s; set<int> t; for(int i : A) { set<int> r; r.insert(i); for(int j : t) r.insert(j | i); t = r; for(int j : t) s.insert(j); } return s.size(); } }; (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |