19.2.12 [LeetCode 70] Climbing Stairs
发布时间:2020-12-14 04:24:50 所属栏目:大数据 来源:网络整理
导读:You are climbing a stair case. It takes? n ?steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note:?Given? n ?will be a positive integer. Example 1: Input: 2Output:
You are climbing a stair case. It takes?n?steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note:?Given?n?will be a positive integer. Example 1: Input: 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps
Example 2: Input: 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step
1 class Solution { 2 public: 3 int climbStairs(int n) { 4 vector<int>dp(n + 1,0); 5 dp[n] = 1; 6 for (int i = n; i >= 0; i--) { 7 if (i + 1 <= n)dp[i] += dp[i + 1]; 8 if (i + 2 <= n)dp[i] += dp[i + 2]; 9 } 10 return dp[0]; 11 } 12 }; 是用n步到达目的地而不是路有n单位长度 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |