加入收藏 | 设为首页 | 会员中心 | 我要投稿 李大同 (https://www.lidatong.com.cn/)- 科技、建站、经验、云计算、5G、大数据,站长网!
当前位置: 首页 > 大数据 > 正文

Serialize and Deserialize Binary Tree

发布时间:2020-12-14 04:21:19 所属栏目:大数据 来源:网络整理
导读:Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer,or transmitted across a network connection link to be reconstructed later in the same or anot

Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer,or transmitted across a network connection link to be reconstructed later in the same or another computer environment.

Design an algorithm to serialize and deserialize a binary tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary tree can be serialized to a string and this string can be deserialized to the original tree structure.

Example:?

You may serialize the following tree:

    1
   /   2   3
     /     4   5

as 
"[1,2,3,null,4,5]"

Clarification:?The above format is the same as?how LeetCode serializes a binary tree. You do not necessarily need to follow this format,so please be creative and come up with different approaches yourself.

Note:?Do not use class member/global/static variables to store states. Your serialize and deserialize algorithms should be stateless.

?

序列化和反序列化二叉树。解法主要是两种层序遍历和前序遍历。

前序遍历基本采用递归写法,需要保存一个全局变量来告诉代码,现在在处理数组的第几个数字。比较麻烦。

所以这里给出层序遍历的代码:

class Codec:

    def serialize(self,root):
        """Encodes a tree to a single string.
        
        :type root: TreeNode
        :rtype: str
        """
        if root is None:
            return ""
        res = []
        queue = collections.deque()
        queue.append(root)
        while queue:
            node = queue.popleft()
            if node:
                res.append(str(node.val))
                queue.append(node.left)
                queue.append(node.right)
            else:
                res.append(#)
        return ",".join(res)          

    def deserialize(self,data):
        """Decodes your encoded data to tree.
        
        :type data: str
        :rtype: TreeNode
        """
        if data == "":
            return None
        res = data.split(,)
        queue = collections.deque()
        root = TreeNode(res[0])
        i = 1
        queue.append(root)
        while queue:
            cur = queue.popleft()
            leftval = res[i]
            if leftval != #:
                left = TreeNode(int(leftval))
                cur.left = left
                queue.append(left)
            i += 1
            rightval = res[i]
            if rightval != #:
                right = TreeNode(int(rightval))
                cur.right = right
                queue.append(right)
            i += 1
        return root     

注意这里的写法对于[1,5]的序列化结果为“1,#,5,#,#,#,#”

同时注意这里的反序列化实际利用第一层只有根节点的信息,所以先放到queue中。

(编辑:李大同)

【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容!

    推荐文章
      热点阅读