2018ICPC青岛区域赛 zoj4062 Plants vs. Zombies
BaoBao and DreamGrid are playing the game?Plants vs. Zombies. In the game,DreamGrid grows plants to defend his garden against BaoBao‘s zombies. Plants vs. Zombies(?) (Image from pixiv. ID: 21790160; Artist: socha) There are??plants in DreamGrid‘s garden arranged in a line. From west to east,the plants are numbered from 1 to??and the?-th plant lies??meters to the east of DreamGrid‘s house. The?-th plant has a defense value of??and a growth speed of?. Initially,??for all?. DreamGrid uses a robot to water the plants. The robot is in his house initially. In one step of watering,DreamGrid will choose a direction (east or west) and the robot moves exactly 1 meter along the direction. After moving,if the?-th plant is at the robot‘s position,the robot will water the plant and??will be added to?. Because the water in the robot is limited,at most??steps can be done. The defense value of the garden is defined as?. DreamGrid needs your help to maximize the garden‘s defense value and win the game. Please note that:
InputThere are multiple test cases. The first line of the input contains an integer?,indicating the number of test cases. For each test case: The first line contains two integers??and??(,?),indicating the number of plants and the maximum number of steps the robot can take. The second line contains??integers??(),where??indicates the growth speed of the?-th plant. It‘s guaranteed that the sum of??in all test cases will not exceed?. OutputFor each test case output one line containing one integer,indicating the maximum defense value of the garden DreamGrid can get. Sample Input2 4 8 3 2 6 6 3 9 10 10 1 Sample Output6 4 HintIn the explanation below,‘E‘ indicates that the robot moves exactly 1 meter to the east from his current position,and ‘W‘ indicates that the robot moves exactly 1 meter to the west from his current position. For the first test case,a candidate direction sequence is {E,E,W,E},so that we have For the second test case,W},so that we have ? ? #include "bits/stdc++.h" using namespace std; typedef long long ll; const int maxn = 1e5 + 100; ll n,m; ll a[maxn]; ll b[maxn]; bool check(ll minn) { for (int i = 0; i < n; i++) { b[i] = (minn + a[i] - 1ll) / a[i]; } ll sum = 0ll; for (int i = 0; i < n; i++) { if (b[i] == 0ll) { if (i != n - 1ll) sum++; } else { sum += b[i] * 2ll - 1ll; b[i + 1] = b[i + 1] - b[i] + 1ll; if (b[i + 1] < 0) b[i + 1] = 0; } if (sum > m) return 0; } return sum <= m; } int main() { //freopen("input.txt","r",stdin); int _; cin >> _; while (_--) { cin >> n >> m; for (int i = 0; i < n; i++) { cin >> a[i]; } ll l = 0,r = 100005 * m; ll mid; while (l < r) { mid = (l + r + 1) / 2; if (check(mid)) { l = mid; } else { r = mid - 1; } } cout << l << endl; } return 0; } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |