536.Construct Binary Tree from String
发布时间:2020-12-14 04:15:28 所属栏目:大数据 来源:网络整理
导读:You need to construct a binary tree from a string consisting of parenthesis and integers.The whole input represents a binary tree. It contains an integer followed by zero,one or two pairs of parenthesis. The integer represents the root ‘s
You need to construct a binary tree from a string consisting of parenthesis and integers. The whole input represents a binary tree. It contains an integer followed by zero,one or two pairs of parenthesis. The integer represents the root‘s value and a pair of parenthesis contains a child binary tree with the same structure. You always start to construct the?left?child node of the parent first if it exists. Example:? Input: "4(2(3)(1))(6(5))" Output: return the tree root node representing the following tree: 4 / 2 6 / / 3 1 5 Note:? 1. There will only be?‘(‘,?‘)‘,?‘-‘?and?‘0‘?~?‘9‘?in the input string. 2. An empty tree is represented by?""?instead of?"()". public class Solution { public TreeNode str2tree(String s) { Stack<TreeNode> stack = new Stack<>(); for(int i = 0,j = i; i < s.length(); i++,j = i){ char c = s.charAt(i); if(c == ‘)‘) stack.pop(); else if(c >= ‘0‘ && c <= ‘9‘ || c == ‘-‘){ while(i + 1 < s.length() && s.charAt(i + 1) >= ‘0‘ && s.charAt(i + 1) <= ‘9‘) i++; TreeNode currentNode = new TreeNode(Integer.valueOf(s.substring(j,i + 1))); if(!stack.isEmpty()){ TreeNode parent = stack.peek(); if(parent.left != null) parent.right = currentNode; else parent.left = currentNode; } stack.push(currentNode); } } return stack.isEmpty() ? null : stack.peek(); } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |