HDU1042(大数运算)
发布时间:2020-12-14 04:10:29 所属栏目:大数据 来源:网络整理
导读:N! Time Limit: 10000/5000 MS (Java/Others)????Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 41734????Accepted Submission(s): 11606 Problem Description Given an integer N(0 ≤ N ≤ 10000),your task is to calculate N! ? ? In
N!Time Limit: 10000/5000 MS (Java/Others)????Memory Limit: 65536/32768 K (Java/Others)
Problem Description
Given an integer N(0 ≤ N ≤ 10000),your task is to calculate N!
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Input
One N in one line,process to the end of file.
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Output
For each N,output N! in one line.
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Sample Input
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Sample Output
? //开辟数组每位存储一个数位,一次用当前数和每一位相乘,注意进位! #include<iostream> using namespace std; #include<stdio.h> const int SUB=40000; int main() { int n,i,j; int a[SUB]; int digit; int carry; int temp; while(scanf("%d",&n)!=EOF) { a[0]=1; digit=1; if(n==0||n==1) { printf("%dn",a[0]); continue; } for(i=2;i<=n;i++) { for(j=0,carry=0;j<digit;j++) { temp=a[j]*i+carry; a[j]=temp%10; carry=temp/10; } if(carry) { while(carry) { a[j++]=carry%10; carry/=10; digit=j; } } } for(i=digit-1;i>=0;i--) { printf("%d",a[i]); } printf("n"); } return 0; } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |