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HDU1592(递推+大数处理)

发布时间:2020-12-14 04:10:24 所属栏目:大数据 来源:网络整理
导读:Half of and a Half Time Limit: 1000/1000 MS (Java/Others)????Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 792????Accepted Submission(s): 350 Problem Description Gardon bought many many chocolates from the A Chocolate Mark

Half of and a Half

Time Limit: 1000/1000 MS (Java/Others)????Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 792????Accepted Submission(s): 350


Problem Description
Gardon bought many many chocolates from the A Chocolate Market (ACM). When he was on the way to meet Angel,he met Speakless by accident.
"Ah,so many delicious chocolates! I'll get half of them and a half!" Speakless said.
Gardon went on his way,but soon he met YZG1984 by accident....
"Ah,so many delicious chocolates! I'll get half of them and a half!" YZG1984 said.
Gardon went on his way,but soon he met Doramon by accident....
"Ah,so many delicious chocolates! I'll get half of them and a half!" Doramon said.
Gardon went on his way,but soon he met JGShining by accident....
"Ah,so many delicious chocolates! I'll get half of them and a half!" JGShining said.
.
.
.
After had had met N people,Gardon finally met Angel. He gave her half of the rest and a half,then Gardon have none for himself. Could you tell how many chocolates did he bought from ACM?
?


?

Input
Input contains many test cases.
Each case have a integer N,represents the number of people Gardon met except Angel. N will never exceed 1000;
?


?

Output
For every N inputed,tell how many chocolates Gardon had at first.
?


?

Sample Input
  
  
2
?


?

Sample Output
  
  
7
?


递推+大数处理

#include<iostream>
using namespace std;
int a[100];

int main() { ?int n,i,j,temp; ?int len; ?while(scanf("%d",&n)!=EOF) ?{ ??memset(a,sizeof(a)); ??len=0; ??a[len]=1; ??for(i=1;i<=n;i++) ??{ ???temp=0; ???for(j=0;j<=len;j++) ???{ ????if(j==0) ?????a[j]=(a[j]+0.5)*2; ????else a[j]=a[j]*2+temp; ????temp=a[j]/10000; ????a[j]=a[j]%10000; ???} ???if(temp) ???{ ????len++; ????a[len]=temp; ???} ??} ??printf("%d",a[len]); ??for(i=len-1;i>=0;i--) ???printf("%04d",a[i]); ??printf("n"); ?? ?} ?return 0; }

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