大数阶乘Java实现
题目
思路:用data数组来存放阶乘的每一位数字,首先令第一位的数值为1,位数为1,然后将每次相乘的乘积存回数组,并循环处理每个数组中超过10的数,若数值超过10,则需要进位,将位数加1,原来的数除以10,商数加前一位数的数值后存回前一位数的数组中,再将余数存回原来位数的数组中。 例如求5!的值 代码如下:
import java.util.*; public class Main { public static void main(String[] args) { Scanner input = new Scanner(System.in); int[] cal = new int[10010]; int num = input.nextInt(); cal[0] = 1; for(int index = 1; index <= num; ++index ) { for(int i = 0; i < 10000; i++) { cal[i] = cal[i]*index; } for(int i = 0; i < 10000; i++) { cal[i+4] = cal[i+4]+ cal[i]/10000; cal[i+3] = cal[i+3]+ cal[i]%10000/1000; cal[i+2] = cal[i+2]+ cal[i]%1000/100; cal[i+1] = cal[i+1]+ cal[i]%100/10; cal[i+0] = cal[i]%10; } } for(int i3 = 0; i3 < 10004; i3++) { cal[i3+4] = cal[i3+4]+ cal[i3]/10000; cal[i3+3] = cal[i3+3]+ cal[i3]%10000/1000; cal[i3+2] = cal[i3+2]+ cal[i3]%1000/100; cal[i3+1] = cal[i3+1]+ cal[i3]%100/10; cal[i3+0] = cal[i3]%10; } int x = 10000; while(cal[x] == 0) x--; for(int i2 = x; i2 >= 0; i2--) { System.out.print(cal[i2]); } System.out.println(); } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |