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314. Binary Tree Vertical Order Traversal

发布时间:2020-12-14 03:49:42 所属栏目:大数据 来源:网络整理
导读:314 . Binary Tree Vertical Order Traversal /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { class Pair{ TreeNode node; I
314. Binary Tree Vertical Order Traversal

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    class Pair{
        TreeNode node;
        Integer pos;
        
        public Pair(TreeNode node,Integer pos){
            this.node = node;
            this.pos = pos;
        }
    }
    public List<List<Integer>> verticalOrder(TreeNode root) {
        HashMap<Integer,List<Integer>> map = new HashMap<>();
        List<List<Integer>> result = new ArrayList<>();
        if(root == null){
            return result;
        }
        
        Queue<Pair> queue = new LinkedList<>();
        Integer max = 0;
        Integer min = 0;
        
        queue.offer(new Pair(root,0));
        while(!queue.isEmpty()){
            Pair cur = queue.poll();
            Integer curPos = cur.pos;
            TreeNode curNode = cur.node;
            
            if(!map.containsKey(curPos)){
                map.put(curPos,new ArrayList<>());
            }
            map.get(curPos).add(curNode.val);
            
            if(curNode.left != null){
                min = Math.min(min,curPos - 1);
                queue.offer(new Pair(curNode.left,curPos - 1));
            }
            
            if(curNode.right != null){
                max = Math.max(max,curPos + 1);
                queue.offer(new Pair(curNode.right,curPos + 1));
            }
        }
        for(int i = min; i <= max; i++){
            
            result.add(map.get(i));
        }
        return result;
    }
}

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