HDOJ 1042 N! -- 大数运算
发布时间:2020-12-14 03:42:35 所属栏目:大数据 来源:网络整理
导读:题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=1042 Problem Description Given an integer N(0 ≤ N ≤ 10000),your task is to calculate N! ? Input One N in one line,process to the end of file. ? Output For each N,output N! in one line.
题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=1042
Problem Description
Given an integer N(0 ≤ N ≤ 10000),your task is to calculate N!
?
Input
One N in one line,process to the end of file.
?
Output
For each N,output N! in one line.
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Sample Input
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Sample Output
#include <stdio.h> #include <string.h> /* 一个数组元素表示 4 个十进制位,即数组是万进制的 */ #define BIG_RADIX 10000 #define RADIX_LEN 4 /* 10000! 有 35660 位 */ #define MAX_LEN (35660/RADIX_LEN + 1) int x[MAX_LEN + 1]; void Big_Print(){ int i; int start_output = 0;//用于跳过多余的0 for (i = MAX_LEN; i >= 0; --i){ if (start_output == 1){//如果多余的0已经跳过,则输出 printf("%04d",x[i]); } else if (x[i] > 0){//表示多余的0已经跳过 printf("%d",x[i]); start_output = 1; } } if (start_output == 0)//如果全为0 printf("0"); } void Big_Multiple(int y){ int i; int carry = 0;//保存进位 int tmp; for (i = 0; i < MAX_LEN; ++i){ tmp = x[i] * y + carry; x[i] = tmp % BIG_RADIX; carry = tmp / BIG_RADIX; } } void Big_Factorial(int N){ int i; memset(x,sizeof(x)); x[0] = 1; for (i = 2; i <= N; ++i){ Big_Multiple(i); } } int main(void){ int N; while (scanf("%d",&N) != EOF){ Big_Factorial(N); Big_Print(); printf("n"); } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |