HDU 1002 大数问题

发布时间：2020-12-14 03:41:16 所属栏目：大数据来源：网络整理

导读：A + B Problem II Time Limit: 2000/1000 MS (Java/Others)????Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 191832????Accepted Submission(s): 36673 Problem Description I have a very simple problem for you. Given two integers

A + B Problem II

Time Limit: 2000/1000 MS (Java/Others)????Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 191832????Accepted Submission(s): 36673

Problem Description

I have a very simple problem for you. Given two integers A and B,your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow,each line consists of two positive integers,A and B. Notice that the integers are very large,that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case,you should output two lines. The first line is "Case #:",# means the number of the test case. The second line is the an equation "A + B = Sum",Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

  
  
   
   2
1 2
112233445566778899 998877665544332211

Sample Output

  
  
   
   Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 2222222222222221110

题目大意：很明显就是两个数相加即可，这里要处理和解决的主要是大数问题：

源代码“：

import java.math.BigDecimal;
import java.io.BufferedInputStream;
import java.util.Scanner;
public class Main {

	/**
	 * @param args
	 */
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner in = new Scanner(new BufferedInputStream(System.in));
		int n,num = 0;
		n = in.nextInt();
		while(n>=1)
		{
			n--;
			num++;
			String a = in.next();
			String b = in.next();
			BigDecimal big1 = new BigDecimal(a);
			BigDecimal big2 = new BigDecimal(b);
			BigDecimal big3;
			big3 = big1.add(big2);
			System.out.println("Case "+num+":");
			System.out.println(a + " + " + b +" = " + big3.toString());
			if(n!=0) System.out.println("");
		}
	}

}

（编辑：李大同）

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