AOAPC_I 高精度运算类 bign
发布时间:2020-12-14 03:34:07 所属栏目:大数据 来源:网络整理
导读:#include cstdio#include cstring#include iostreamusing namespace std;const int MAXN = 200;struct bign{ int len,s[MAXN]; bign() { memset(s,sizeof(s)); len = 1; } bign(int num) { *this = num; } bign(const char* num) { *this = num; } bign oper
#include <cstdio> #include <cstring> #include <iostream> using namespace std; const int MAXN = 200; struct bign { int len,s[MAXN]; bign() { memset(s,sizeof(s)); len = 1; } bign(int num) { *this = num; } bign(const char* num) { *this = num; } bign operator = (int num) { char s[MAXN]; sprintf(s,"%d",num); *this = s; return *this; } bign operator = (const char* num) { len = strlen(num); for(int i = 0; i < len; i++) s[i] = num[len-i-1] - '0'; return *this; } string str() const { string res = ""; for(int i = 0; i < len; i++) res = (char)(s[i] + '0') + res; if(res == "") res = "0"; return res; } bign operator + (const bign& b) const { bign c; c.len = 0; for(int i = 0,g = 0; g || i < max(len,b.len); i++) { int x = g; if(i < len) x += s[i]; if(i < b.len) x += b.s[i]; c.s[c.len++] = x % 10; g = x / 10; } return c; } void clean() { while(len > 1 && !s[len-1]) len--; } bign operator * (const bign& b) { bign c; c.len = len + b.len; for(int i = 0; i < len; i++) for(int j = 0; j < b.len; j++) c.s[i+j] += s[i] * b.s[j]; for(int i = 0; i < c.len-1; i++) { c.s[i+1] += c.s[i] / 10; c.s[i] %= 10; } c.clean(); return c; } bign operator - (const bign& b) { bign c; c.len = 0; for(int i = 0,g = 0; i < len; i++) { int x = s[i] - g; if(i < b.len) x -= b.s[i]; if(x >= 0) g = 0; else { g = 1; x += 10; } c.s[c.len++] = x; } c.clean(); return c; } bool operator < (const bign& b) const { if(len != b.len) return len < b.len; for(int i = len-1; i >= 0; i--) if(s[i] != b.s[i]) return s[i] < b.s[i]; return false; } bool operator > (const bign& b) const { return b < *this; } bool operator <= (const bign& b) { return !(b > *this); } bool operator == (const bign& b) { return !(b < *this) && !(*this < b); } bign operator += (const bign& b) { *this = *this + b; return *this; } }; istream& operator >> (istream &in,bign& x) { string s; in >> s; x = s.c_str(); return in; } ostream& operator << (ostream &out,const bign& x) { out << x.str(); return out; } int main() { bign a; cin >> a; cout << a*a << endl; a += "123456789123456789000000000"; cout << a*2 << endl; return 0; } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |