LeetCode 108 Convert Sorted Array to Binary Search Tree
发布时间:2020-12-14 03:23:15 所属栏目:大数据 来源:网络整理
导读:Given an array where elements are sorted in ascending order,convert it to a height balanced BST. For this problem,a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of? every ?node never differ
Given an array where elements are sorted in ascending order,convert it to a height balanced BST. For this problem,a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of?every?node never differ by more than 1. Example:
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把一个升序序列变成一个平衡二叉搜索树:
c++
class Solution { public: TreeNode* sortedArrayToBST(vector<int>& nums) { if(nums.empty()) return NULL; int l = 0 ; int r = nums.size()-1; int mid = (l+r)/2 ; vector<int> left; vector<int> right; for(int i=0;i<mid;i++) left.push_back(nums[i]); for(int i=mid+1;i<=r;i++) right.push_back(nums[i]); TreeNode* tree = new TreeNode(nums[mid]); tree->left = sortedArrayToBST(left); tree->right = sortedArrayToBST(right); return tree; } }; (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |