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Product //大数相乘

发布时间:2020-12-14 02:53:56 所属栏目:大数据 来源:网络整理
导读:#include stdio.h#include string.h#define N 1000void yiwei(char *ch,int a);void add(char *ch1,char *ch2);void rev(char *ch);int main(){ char ch1[N],ch2[N],ch3[N],ch4[N];int i,j,k; while(scanf("%s %s",ch1,ch2) != -1) { rev(ch1);rev(ch2); mem
#include <stdio.h>
#include <string.h>

#define N 1000
void yiwei(char *ch,int a);
void add(char *ch1,char *ch2);
void rev(char *ch);

int main()
{
    char ch1[N],ch2[N],ch3[N],ch4[N];
	int i,j,k;

    while(scanf("%s %s",ch1,ch2) != -1)
    {
        rev(ch1);rev(ch2);
        memset(ch4,sizeof(ch4));

        for( i=0; ch1[i]!=0; i++)
        {
            memset(ch3,sizeof(ch3));
            for( j=0; ch2[j]!=0; j++)       //ch3中存的是对应位乘积+1,不加1可能为0了。
            {
                ch3[j] =  (ch1[i]-'0')*(ch2[j]-'0')+1;
            }
            for( k=0; ch3[k]; k++)
            {
                if(ch3[k]-1 > 9)
                {
					if(!ch3[k+1])
					{
						ch3[k+1] += (ch3[k]-1)/10+1;
						ch3[k] = (ch3[k]-1)%10+1;
					}
					else
					{
						ch3[k+1] += (ch3[k]-1)/10;
						ch3[k] = (ch3[k]-1)%10+1;
					}
                }
           } 
			k = 0;
			 while(ch3[k])
			 {	
				 ch3[k] = ch3[k]-1+'0';	
				 k++;
			 }
            yiwei(ch3,i);
            add(ch4,ch3);
        }

        rev(ch4);

		if(ch4[0]=='0')
			ch4[1] = 0;

        printf("%sn",ch4);
    }
    return 0;
}
void yiwei(char *ch,int a)
{
    int len,i;
    len = strlen(ch);
    for( i=len+a; i>=a; i--)
    {
        ch[i] = ch[i-a];
    }
    for(i=0; i<a; i++)
        ch[i] = '0';
}
void add(char *ch1,char *ch2)
{
    int i = 0;
    while(ch1[i] || ch2[i])
    {
        if(!ch1[i] || !ch2[i])
            ch1[i] = ch1[i]+ch2[i];
        else
            ch1[i] = ch1[i]+ch2[i]-'0';
		i++;
    }
    i = 0;
    while(ch1[i])
    {
        if(ch1[i] > '9')
        {
            if(!ch1[i+1])
            {
                ch1[i+1] += (ch1[i]-'0')/10+'0';
                ch1[i] = '0'+(ch1[i]-'0')%10;
            }
            else
            {
                ch1[i+1] += (ch1[i]-'0')/10;
                ch1[i] = '0'+(ch1[i]-'0')%10;
            }
        }
		i++;
    }
}
void rev(char *ch)
{
	int len,i;
	char ch1[N];
	len = strlen(ch);
	for(i=0; i<len; i++)
		ch1[len-i-1] = ch[i];
	for(i=0; i<len; i++)
		ch[i] = ch1[i];
}







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