hdoj 1002 A+B Problem II

原来一直比较烦大数题，写了两个慢慢好了，几点注意以下

1.变量名以后要养成习惯和规律

2. printf输出string要转换成c_str()

/*
PROG:A + B Problem
LANG: C++11 
*/
#include <cstdio>
#include <cmath>
#include <cstring>
#include <string>
#include <cstdlib>
#include <climits>
#include <ctype.h>
#include <queue>
#include <stack>
#include <vector>
#include <utility>
#include <deque>
#include <set>
#include <map>
#include <iostream>
#include <fstream>
#include <algorithm>
#include <time.h>

using namespace std;
#define mst(a,b) memset(a,b,sizeof(a))

typedef long long ll;
const int N = 100010;
const ll MOD = 1000000007;
const int INF = 0x7fffffff;

void solve(string s1,string s2,int t,int tt){
    int m = s1.size()-1;
    int n = s2.size()-1;
    int carry = 0;
    int d1,d2;
    string ans;
    for(int i = m,j = n; i >= 0 || j >= 0 || carry ; i--,j--){
        d1 = i >= 0 ? int(s1[i] - '0') : 0;
        d2 = j >= 0 ? int(s2[j] - '0') : 0;
        carry = carry + d1 + d2;
        ans = (char) (carry%10 + '0') + ans;
        carry /= 10;
    }
    printf("Case %d:n",t);
    printf("%s + %s = %sn",s1.c_str(),s2.c_str(),ans.c_str());
    if(t != tt)
        printf("n");
}

int main()
{
    int n;
    cin >> n;
    string s1,s2;
    for(int i = 1; i <= n; i++){
        cin >> s1 >> s2;
        solve(s1,s2,i,n);
    }
    return 0;
}