LightOJ 1214（大数相除）

Given two integers,?a?and?b,you should check whether?a?is divisible by?b?or not. We know that an integer?a?is divisible by an integer?b?if and only if there exists an integer?c?such that?a = b * c.

Input starts with an integer?T (≤ 525),denoting the number of test cases.

Each case starts with a line containing two integers?a (-10²⁰⁰?≤ a ≤ 10²⁰⁰)?and?b (|b| > 0,b fits into a 32 bit signed integer). Numbers will not contain leading zeroes.

For each case,print the case number first. Then print?'divisible'?if?a?is divisible by?b. Otherwise print?'not divisible'.

6

101 101

0 67

-101 101

7678123668327637674887634 101

11010000000000000000 256

-202202202202000202202202 -101

Case 1: divisible

Case 2: divisible

Case 3: divisible

Case 4: not divisible

Case 5: divisible

Case 6: divisible

直接上Java

import java.io.*;
import java.util.*;
import java.math.*;

public class Main {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner in = new Scanner(System.in);
		BigInteger a,b;
		int t;
		t = in.nextInt();
		for (int i = 1; i <= t; i++) {
			a = in.nextBigInteger();
			b = in.nextBigInteger();
			if(b.compareTo(BigInteger.ZERO)<0) b=b.multiply(BigInteger.valueOf(-1));
			BigInteger c = a.mod(b);
			if (c == BigInteger.ZERO)
				System.out.println("Case " + i + ": " + "divisible");
			else
				System.out.println("Case " + i + ": " + "not divisible");
		}
	}

}