Given two integers,a and b,you should checkwhether a is divisible by b or not. We know that an integer ais divisible by an integer b if and only if there exists an integer csuch that a = b * c.

Input

Input starts with an integer T (≤ 525),denoting the number of test cases.

Each case starts with a line containing two integers a(-10²⁰⁰ ≤ a ≤ 10²⁰⁰) and b (|b| >0,b fits into a 32 bit signed integer). Numbers will not contain leadingzeroes.

Output

For each case,print the case number first. Then print 'divisible'if a is divisible by b. Otherwise print 'not divisible'.

?

double类型不可以取余；

#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#define LL long long
using namespace std;
char s[400];
int main()
{
    LL n,m,i,x,y;
    LL cla;
    bool bj;
    scanf("%lld",&cla);
    for(int gr=1; gr<=cla; gr++)
    {
        bj=true;
        scanf("%s%lld",s,&m);
        printf("Case %lld: ",gr);
        x=0;
        for(i=0;i<strlen(s);i++)//一个大数一个整数的类型，处理的话枚举大数的每个字符一位一位的进行取余
        {
            if(s[i]=='-')
            continue;
            x=(x*10+s[i]-'0')%m;
        }
        if(!x)//最终的结果是否为0
            printf("divisiblen");
        else
            printf("not divisiblen");
    }
    return 0;
}