POJ 2506 Tiling(大数版递推)

发布时间：2020-12-14 02:21:01 所属栏目：大数据来源：网络整理

导读：Tiling Time Limit: ?1000MS ? Memory Limit: ?65536K Total Submissions: ?8334 ? Accepted: ?4023 Description In how many ways can you tile a 2xn rectangle by 2x1 or 2x2 tiles?? Here is a sample tiling of a 2x17 rectangle.? Input Input is a se

Tiling

Time Limit:?1000MS	?	Memory Limit:?65536K
Total Submissions:?8334	?	Accepted:?4023

Description

In how many ways can you tile a 2xn rectangle by 2x1 or 2x2 tiles??
Here is a sample tiling of a 2x17 rectangle.?

Input

Input is a sequence of lines,each line containing an integer number 0 <= n <= 250.

Output

For each line of input,output one integer number in a separate line giving the number of possible tilings of a 2xn rectangle.?

Sample Input

Sample Output

3
171
2731
845100400152152934331135470251
1071292029505993517027974728227441735014801995855195223534251

看这题前可以先做做这题HDOJ 2501； 由此题找出规律后即可用大数解决这一道题。

具体代码如下： ??

<span style="font-size:18px;">#include<cstdio>
#include<cstring> 
int a[260][2010];

void count()
{
	int i,j,k,s;
	memset(a,sizeof(a));
	a[0][0]=1;
	a[1][0]=1;
	a[2][0]=3;
	for(i=3;i<260;++i)
	{
		k=0;
		for(j=0;j<=2000;++j)
		{
			s=a[i-1][j]+2*a[i-2][j]+k;
			a[i][j]=s%10;
			k=s/10;
		}
	}
}

int main()
{
	count();
	int n,i;
	while(scanf("%d",&n)!=EOF)
	{
		for(i=2000;i>=0;i--)
		   if(a[n][i])
		      break;
		for(;i>=0;i--)
		   printf("%d",a[n][i]);
		printf("n");
	}
	return 0;
}</span>

（编辑：李大同）

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