poj 3181 Dollar Dayz 钱币兑换问题 大数/高精度 完全背包
发布时间:2020-12-14 02:10:54 所属栏目:大数据 来源:网络整理
导读:Dollar Dayz Time Limit: ?1000MS ? Memory Limit: ?65536K Total Submissions: ?5289 ? Accepted: ?2006 Description Farmer John goes to Dollar Days at The Cow Store and discovers an unlimited number of tools on sale. During his first visit,the
Dollar Dayz
Description
Farmer John goes to Dollar Days at The Cow Store and discovers an unlimited number of tools on sale. During his first visit,the tools are selling variously for $1,$2,and $3. Farmer John has exactly $5 to spend. He can buy 5 tools at $1 each or 1 tool at $3 and an additional 1 tool at $2. Of course,there are other combinations for a total of 5 different ways FJ can spend all his money on tools. Here they are:?
1 @ US$3 + 1 @ US$2 1 @ US$3 + 2 @ US$1 1 @ US$2 + 3 @ US$1 2 @ US$2 + 1 @ US$1 5 @ US$1Write a program than will compute the number of ways FJ can spend N dollars (1 <= N <= 1000) at The Cow Store for tools on sale with a cost of $1..$K (1 <= K <= 100). Input
A single line with two space-separated integers: N and K.
Output
A single line with a single integer that is the number of unique ways FJ can spend his money.
Sample Input 5 3 Sample Output 5 Source
USACO 2006 January Silver
竟然必须用高精度,如何能看出来呢? import java.math.*; import java.util.Scanner; public class Main { static Scanner cin=new Scanner(System.in); static int V,n; static final int maxn= 100+5; static final int maxV= 1000+20; static BigInteger [] dp=new BigInteger [maxV]; static int [] cost =new int [maxn ]; static void pre() { for(int i=1;i<=100;i++) { cost[i]=i; } } public static void main(String args[]) { pre(); while(cin.hasNextInt() ) { V=cin.nextInt(); n=cin.nextInt(); for(int i=1;i<=V;i++) dp[i]=BigInteger.ZERO; dp[0]=BigInteger.ONE; for(int i=1;i<=n;i++) { for(int v=cost[i];v<=V;v++) { dp[v]=dp[v].add(dp[v-cost[i] ]); } } System.out.println(dp[V]); } } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |