大数相加
发布时间:2020-12-14 01:32:30 所属栏目:大数据 来源:网络整理
导读:/** * Created by syh on 2016/9/20. * 大数相加 */public class BigNumber { public static void main(String[] args) { String num1 = "1045"; String num2 = "55"; System.out.println(add(num1,num2)); } /** * 用字符串模拟两个大数相加 */ public stat
/** * Created by syh on 2016/9/20. * 大数相加 */ public class BigNumber { public static void main(String[] args) { String num1 = "1045"; String num2 = "55"; System.out.println(add(num1,num2)); } /** * 用字符串模拟两个大数相加 */ public static String add(String n1,String n2) { StringBuilder result = new StringBuilder(); // 1 反转字符串 String number1 = new StringBuffer(n1).reverse().toString(); String number2 = new StringBuffer(n2).reverse().toString(); // 2 把两个字符串补齐,即短字符串的高位用0补齐 int len1 = number1.length(); int len2 = number2.length(); int maxLen = len1 > len2 ? len1 : len2; if (len1 < len2) { for (int i = len1; i < len2; i++) { number1 += "0"; } } else if (len1 > len2) { for (int i = len2; i < len1; i++) { number2 += "0"; } } // 3 把两个正整数相加,一位一位的加并加上进位 boolean overFlow = false; //是否进位 for (int i = 0; i < maxLen; i++) { int sum = Integer.parseInt(number1.charAt(i) + "") + Integer.parseInt(number2.charAt(i) + ""); if (overFlow) { sum += 1; } if (sum >= 10) { overFlow = true; result.append(sum - 10); } else { overFlow = false; result.append(sum); } } // 4 最高位 if (overFlow) { result.append("1"); } return result.reverse().toString(); } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |