ruby-on-rails – Ruby on Rails平均方法导致n 1个查询
发布时间:2020-12-17 04:16:06 所属栏目:百科 来源:网络整理
导读:我有以下脚本: User.includes(:owned_ratings).map{|x| x.owned_ratings.average(:score)} 调用x.owned_ratings.average(:score)会导致n 1个查询: (0.2ms) SELECT AVG("ratings"."score") FROM "ratings" INNER JOIN "video_chats" ON "ratings"."video_c
我有以下脚本:
User.includes(:owned_ratings).map{|x| x.owned_ratings.average(:score)} 调用x.owned_ratings.average(:score)会导致n 1个查询: (0.2ms) SELECT AVG("ratings"."score") FROM "ratings" INNER JOIN "video_chats" ON "ratings"."video_chat_id" = "video_chats"."id" WHERE "video_chats"."user_id" = $1 [["user_id",4]] (0.1ms) SELECT AVG("ratings"."score") FROM "ratings" INNER JOIN "video_chats" ON "ratings"."video_chat_id" = "video_chats"."id" WHERE "video_chats"."user_id" = $1 [["user_id",1]] (0.1ms) SELECT AVG("ratings"."score") FROM "ratings" INNER JOIN "video_chats" ON "ratings"."video_chat_id" = "video_chats"."id" WHERE "video_chats"."user_id" = $1 [["user_id",5]] (0.1ms) SELECT AVG("ratings"."score") FROM "ratings" INNER JOIN "video_chats" ON "ratings"."video_chat_id" = "video_chats"."id" WHERE "video_chats"."user_id" = $1 [["user_id",7]] (0.1ms) SELECT AVG("ratings"."score") FROM "ratings" INNER JOIN "video_chats" ON "ratings"."video_chat_id" = "video_chats"."id" WHERE "video_chats"."user_id" = $1 [["user_id",3]] 为什么包含不使用聚合方法?有什么方法可以解决这个问题吗?我知道我可以自己实现平均方法并省略问题,但我想确保没有更好的解决方案. 解决方法
因为在ruby中重新实现聚合方法没有意义,所以当数据库服务器可以更快地完成工作时. 实际上,如果这是您需要做的,那么准备和执行原始SQL查询可能会更好,因此整个迭代都在数据库中完成,因此避免了往返和N 1(更不用说加载所有内容). (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |