如何在Ruby中检查数组中的范围？

require 'set'
STRAIGHTS = ['A',*2..9,'T','J','Q','K','A'].each_cons(5).map(&:to_set)
  #=> [#<Set: {"A",2,5}>,#<Set: {2,6}>,#   ...#<Set: {9,"K"}>,#<Set: {"T","A"}>]

def straight?(hand)
  STRAIGHTS.include?(hand.to_set)
end

STRAIGHTS.include?([6,2].to_set)
  # STRAIGHTS.include?(#<Set: {6,2}>)
  #=> true 

straight?([6,2])            #=> true 
straight?(["T","A"])  #=> true 
straight?(["A","T"])  #=> true
straight?([2,"A"])          #=> true 

straight?([6,"J"])          #=> false 
straight?(["J","T"])        #=> false

编辑1：@mudasobwa通过指出’A’,5是有效的直线来扰乱苹果车.我相信我已经解决了问题. (我相信他不会告诉我’K’,’A’,4也是有效的.)

我建议如下：

CARDS     = [2,"A"]
STRAIGHTS = CARDS.each_cons(5).to_a
  #=>[[2,6],[3,7],[4,8],#   [5,9],[6,"T"],[7,"J"],#   [8,"Q"],[9,"K"],#   ["T","A"]] 

def straight?(hand)
  (hand.map {|c| CARDS.index(c)}.sort == [0,1,12]) ||
  STRAIGHTS.include?(hand.sort {|a,b| CARDS.index(a) <=> CARDS.index(b)})
end