数组 – 从多个范围构建数组
发布时间:2020-12-17 03:56:34 所属栏目:百科 来源:网络整理
导读:我想用几个范围构建一个数组.以下作品: array_of_ranges = (70..89).to_a + (184..193).to_a + (224..233).to_a + (296..304).to_a + (336..345).to_a = [70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,184,185,186,187,188,189,190,191,19
我想用几个范围构建一个数组.以下作品:
array_of_ranges = (70..89).to_a + (184..193).to_a + (224..233).to_a + (296..304).to_a + (336..345).to_a => [70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,184,185,186,187,188,189,190,191,192,193,224,225,226,227,228,229,230,231,232,233,296,297,298,299,300,301,302,303,304,336,337,338,339,340,341,342,343,344,345] 它肯定比键入一堆数字要好得多 – 但我怀疑有一个更好,更清洁的方法来做到这一点.有任何想法吗? 解决方法
您可以使用splat运算符非常干净地执行此操作:
[*70..89,*184..193,*224..233,*296..304,*336..345] 结果: [70,345] (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |