ruby-on-rails – 使用Active Record Reputation System gem,当

def index
  @microposts = Micropost.paginate(page: params[:page]).find_with_reputation(:votes,:all,order: "votes desc")
  @micropost  = current_user.microposts.build
end

但是除了我在模型中设置的默认范围之外,我的索引操作中没有排序

在我的微博模型中,我有

class Micropost < ActiveRecord::Base
    belongs_to :user
    has_many :retweets
    has_reputation :votes,source: :user,aggregated_by: :sum
    default_scope -> { order('created_at DESC') }

如果我将默认范围更改为

default_scope -> { order('votes DESC') }

它的工作方式只是我想要的索引页面,但打破了我的所有其他页面.

我尝试删除默认范围并留在find_with_reputation方法中,但它仍然没有按投票排序.

我也尝试在像这样的微博模型中的方法中定义范围

def self.popular
    find_with_reputation(:votes,{:order => 'votes desc'})
  end

并像这样在microposts_controller中创建代码

def index
    @microposts = Micropost.paginate(page: params[:page]).popular
    @micropost  = current_user.microposts.build
  end

它仍然没有按投票排序.

这是访问微博索引页面的日志输出的副本
https://gist.github.com/anonymous/9745552

这是宝石https://github.com/NARKOZ/activerecord-reputation-system/tree/rails4的链接

我的routes.rb用于微博看起来像这样

resources :microposts,only: [:create,:destroy,:index] do
    member { post :vote }
    member { post :retweet}
  end

任何指导表示赞赏.

更新

我的主页设计的设计与我为Micropost Index Feed所做的设计不同.也许比较有效的东西将有助于查明问题.

我有一个静态页面控制器,它设置这样的家庭行动的范围

def home
      @micropost  = current_user.microposts.build
      @feed_items = current_user.feed.paginate(page: params[:page])
end

在用户模型中,我定义静态页面控制器中使用的feed方法,如此

def feed
  Micropost.from_users_followed_by_including_replies(self)
end

from_users_followed_by_including_replies(self)方法是我在微博模型中设置的范围

scope :from_users_followed_by_including_replies,lambda { |user| followed_by_including_replies(user) }

 def self.followed_by_including_replies(user)
      followed_ids = %(SELECT followed_id FROM relationships
                       WHERE follower_id = :user_id)
      where("user_id IN (#{followed_ids}) OR user_id = :user_id OR to_id = :user_id",{ :user_id => user })
 end

也许我需要对Microposts控制器的Index操作采用类似的方法