ruby-on-rails – 在预先加载的关联上指定条件返回ActiveRecord
发布时间:2020-12-17 02:14:21 所属栏目:百科 来源:网络整理
导读:问题是,当餐厅没有任何符合条件的MenuItem时,ActiveRecord说它找不到餐厅.这是相关的代码: class Restaurant ActiveRecord::Base has_many :menu_items,dependent: :destroy has_many :meals,through: :menu_items def self.with_meals_of_the_week include
问题是,当餐厅没有任何符合条件的MenuItem时,ActiveRecord说它找不到餐厅.这是相关的代码:
class Restaurant < ActiveRecord::Base has_many :menu_items,dependent: :destroy has_many :meals,through: :menu_items def self.with_meals_of_the_week includes({menu_items: :meal}).where(:'menu_items.date' => Time.now.beginning_of_week..Time.now.end_of_week) end end 并生成的sql代码: Restaurant Load (0.0ms)←[0m ←[1mSELECT DISTINCT "restaurants".id FROM "restaurants" LEFT OUTER JOIN "menu_items" ON "menu_items"."restaurant_id" = "restaurants"."id" LEFT OUTER JOIN "meals" ON "meals"."id" = "menu_items"."meal_id" WHERE "restaurants"."id" = ? AND ("menu_items"."date" BETWEEN '2012-10-14 23:00:00.000000' AND '2012-10-21 22:59:59.999999') LIMIT 1←[0m [["id","1"]] 但是,根据Rails Guides的这一部分,这不应该发生: Post.includes(:comments).where("comments.visible",true) 如果在此包含查询的情况下,没有任何帖子的评论,则仍会加载所有帖子. 解决方法
生成的SQL是您查询的正确翻译.但看看它,
只是在SQL级别(我缩短了一点): SELECT * FROM "restaurants" LEFT OUTER JOIN "menu_items" ON "menu_items"."restaurant_id" = "restaurants"."id" LEFT OUTER JOIN "meals" ON "meals"."id" = "menu_items"."meal_id" WHERE "restaurants"."id" = ? AND ("menu_items"."date" BETWEEN '2012-10-14' AND '2012-10-21') 左外联接完成了你期望他们做的工作:餐馆 现在看看在哪里的第二部分:BETWEEN操作符要求, 所以我们需要以使null-date ok的方式更改查询. 回到ruby,你可以写: def self.with_meals_of_the_week includes({menu_items: :meal}) .where('menu_items.date is NULL or menu_items.date between ? and ?',Time.now.beginning_of_week,Time.now.end_of_week ) end 结果SQL现在 .... WHERE (menu_items.date is NULL or menu_items.date between '2012-10-21' and '2012-10-28') 以及没有用餐的餐馆. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |