ruby-on-rails – Active在单个字段上记录多个条件
发布时间:2020-12-17 01:56:55 所属栏目:百科 来源:网络整理
导读:我有以下模型关联: class PartOfSpeech ActiveRecord::Base has_many :part_of_speech_words has_many :words,through: :part_of_speech_wordsendclass Word ActiveRecord::Base has_many :part_of_speech_words has_many :part_of_speeches,through: :part
我有以下模型关联:
class PartOfSpeech < ActiveRecord::Base has_many :part_of_speech_words has_many :words,through: :part_of_speech_words end class Word < ActiveRecord::Base has_many :part_of_speech_words has_many :part_of_speeches,through: :part_of_speech_words end class PartOfSpeechWord < ActiveRecord::Base belongs_to :part_of_speech belongs_to :word end 我给出了一组part_of_speech_ids说[1,2,3].通过这些关联,我必须找到具有所有这些part_of_speeches的所有单词.必须显示part_of_speech_ids [1,3,4]的单词,但不能只显示[1,2]. 使用IN查询将无法在执行OR运算时给出正确的结果.我想要在数组元素上执行AND的东西. 请帮忙. 解决方法
鉴于您在连接表中有word_id和part_of_speech_id的唯一索引,您只需计算数学记录:
word_ids = PartOfSpeechWord. select('min(word_id) AS word_id'). where(part_of_speech_id: part_of_speech_ids). group_by(:part_of_speech_id). having('COUNT(part_of_speech_id) >= ?',part_of_speech_ids.size). map { |x| x['word_id'] } word = Word.where(id: word_ids) (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |