ruby – 如何查看哪种方法运行得更快

发布时间：2020-12-17 01:34:40 所属栏目：百科来源：网络整理

导读：如何确定哪种方法运行得更快？很难在 Ruby文档中阅读Benchmark并实际实现它.谢谢 def count_between(list_of_integers,lower_bound,upper_bound) count = 0 list_of_integers.each do |x| (x = lower_bound x = upper_bound) ? count += 1 : next end counte

如何确定哪种方法运行得更快？很难在 Ruby文档中阅读Benchmark并实际实现它.谢谢

def count_between(list_of_integers,lower_bound,upper_bound)
  count = 0
  list_of_integers.each do |x|
    (x >= lower_bound && x <= upper_bound) ? count += 1 : next
  end
  count
end

要么

def count_between(list_of_integers,upper_bound)
 count = 0
 list_of_integers.each do |x|
   count += 1 if x.between?(lower_bound,upper_bound) 
 end
 count
end

解决方法

require 'benchmark'

def count_between_1(list_of_integers,upper_bound)
  count = 0
  list_of_integers.each do |x|
    (x >= lower_bound && x <= upper_bound) ? count += 1 : next
  end
  count
end

def count_between_2(list_of_integers,upper_bound)
  count = 0
  list_of_integers.each do |x|
    count += 1 if x.between?(lower_bound,upper_bound)
  end
  count
end

list_of_integers = (1..100_000).to_a
lower_bound = 5
upper_bound = 80_000

Benchmark.bm do |x|
  x.report do
    count_between_1(list_of_integers,upper_bound)
  end

  x.report do
    count_between_2(list_of_integers,upper_bound)
  end
end

结果如下：

user     system      total        real
 0.010000   0.000000   0.010000 (  0.008910)
 0.010000   0.000000   0.010000 (  0.018098)

所以第一个变种要快得多.

（编辑：李大同）

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