如何从xml和java中的根元素中删除xmlns属性

发布时间：2020-12-16 23:12:37 所属栏目：百科来源：网络整理

导读：我想从以下xml字符串中删除xmlns属性.我编写了一个 java程序,但不确定它是否需要在这里完成. 如何删除xmlns属性并获取修改后的xml字符串？输入XML字符串： ?xml version="1.0" encoding="UTF-8"?Payment xmlns="http://api.com/schema/store/1.0" Storeabc/

我想从以下xml字符串中删除xmlns属性.我编写了一个 java程序,但不确定它是否需要在这里完成.

如何删除xmlns属性并获取修改后的xml字符串？

输入XML字符串：

<?xml version="1.0" encoding="UTF-8"?>
<Payment xmlns="http://api.com/schema/store/1.0">
    <Store>abc</Store>
</Payment>

预期的XML输出字符串：

<?xml version="1.0" encoding="UTF-8"?>
<Payment>
    <Store>abc</Store>
</Payment>

Java类：

public class XPathUtils {

    public static void main(String[] args) {
        String xml = "<?xml version="1.0" encoding="UTF-8"?><Payment xmlns="http://api.com/schema/store/1.0"><Store>abc</Store></Payment>";
        String afterNsRemoval = removeNameSpace(xml);
        System.out.println("afterNsRemoval = " + afterNsRemoval);
    }

    public static String removeNameSpace(String xml) {
        try {
            System.out.println("before xml = " + xml);
            DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
            DocumentBuilder builder = factory.newDocumentBuilder();
            InputSource inputSource = new InputSource(new StringReader(xml));
            Document xmlDoc = builder.parse(inputSource);
            Node root = xmlDoc.getDocumentElement();
            NodeList rootchildren = root.getChildNodes();
            Element newroot = xmlDoc.createElement(root.getNodeName());
            for (int i = 0; i < rootchildren.getLength(); i++) {
                newroot.appendChild(rootchildren.item(i).cloneNode(true));
            }
            xmlDoc.replaceChild(newroot,root);
            return xmlDoc.toString();
        } catch (Exception e) {
            System.out.println("Could not parse message as xml: " + e.getMessage());
        }
        return "";
    }
}

输出：

before xml = <?xml version="1.0" encoding="UTF-8"?><Payment xmlns="http://api.com/schema/store/1.0"><Store>abc</Store></Payment>

afterNsRemoval = [#document: null]

解决方法

这是使用XPath和vtd-xml(我是作者)的代码…

import com.ximpleware.*;
import java.io.*;

public class removeAttrNode {
    public static void main(String[] s) throws VTDException,Exception{
        VTDGen vg = new VTDGen(); ByteArrayOutputStream baos = new ByteArrayOutputStream();
        String xml = "<?xml version="1.0" encoding="UTF-8"?><Payment xmlns="http://api.com/schema/store/1.0"><Store>abc</Store></Payment>";
        vg.setDoc(xml.getBytes());
        vg.parse(false); // turn off namespace awareness so that 
        VTDNav vn = vg.getNav();
        AutoPilot ap = new AutoPilot(vn);
        XMLModifier xm = new XMLModifier(vn);
        ap.selectXPath("//@xmlns");
        int i=0;
        while((i=ap.evalXPath())!=-1){
            xm.remove();
        }
        xm.output(baos);
        System.out.println(baos.toString());    
    }
}

（编辑：李大同）

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