使用XSLT的XML父子连接
发布时间:2020-12-16 22:52:04 所属栏目:百科 来源:网络整理
导读:INPUT XML: ?xml version="1.0" encoding="ISO-8859-1"?systemmap name="Map" map name="Map1" colorMap1 is red colored/color shapeMap1 is square shaped/shape /map map name="Map2" colorMap2 is green colored/color map name="Tap1" colorTap1 is ye
INPUT
XML:
<?xml version="1.0" encoding="ISO-8859-1"?> <system> <map name="Map"> <map name="Map1"> <color>Map1 is red colored</color> <shape>Map1 is square shaped</shape> </map> <map name="Map2"> <color>Map2 is green colored</color> <map name="Tap1"> <color>Tap1 is yellow colored</color> <speed>Tap1 is very fast</speed> </map> <map name="Tap2"> <speed>Tap2 is very slow</speed> </map> </map> </map> </system> 期望的输出: <?xml version="1.0" encoding="ISO-8859-1"?> <system> <map name="Map+Map1"> <color>Map1 is red colored</color> <shape>Map1 is square shaped</shape> </map> <map name="Map+Map2"> <color>Map2 is green colored</color> </map> <map name="Map+Map2+Tap1"> <color>Tap1 is yellow colored</color> <speed>Tap1 is very fast</speed> </map> <map name="Map+Map2+Tap2"> <speed>Tap2 is very slow</speed> </map> 当前输出: <system> <map name="Map1"/> <map name="Map1"/> <map name="Map2"/> <map name="Map2.Tap1"/> <map name="Map2.Tap1"/> <map name="Map2.Tap2"/> </system> 当前的XSL样式表: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes"/> <xsl:template match="map[@name]"> <xsl:apply-templates mode="next"> <xsl:with-param name="name" select="''" /> </xsl:apply-templates> </xsl:template> <xsl:template match="map[@name]" mode="next"> <xsl:param name="name" /> <xsl:apply-templates mode="next"> <xsl:with-param name="name" select="concat($name,'.',@name)" /> </xsl:apply-templates> </xsl:template> <xsl:template match="*[not(*)]" mode="next"> <xsl:param name="name" /> <xsl:element name="map"> <xsl:attribute name="name"> <xsl:variable name="nameLength" select="string-length($name)-1"/> <xsl:value-of select="substring($name,2,$nameLength)"/> </xsl:attribute> </xsl:element> </xsl:template> <xsl:template match="@*|node()|*"> <xsl:copy> <xsl:apply-templates select="@*|node()|*"/> </xsl:copy> </xsl:template> </xsl:stylesheet> 我只是XSL的初学者.我在网上提到了很多,并试图解决这个问题. 解决方法
你可以尝试这样的事情:
<?xml version="1.0" encoding="utf-8" ?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes"/> <xsl:template match="map" mode="concat" > <xsl:param name="names" select="''" /> <xsl:variable name="newName" select="concat($names,@name)" /> <xsl:copy> <xsl:attribute name ="name"> <xsl:value-of select="$newName"/> </xsl:attribute> <xsl:copy-of select="*[name() != 'map']"/> </xsl:copy> <xsl:apply-templates select="map" mode ="concat"> <xsl:with-param name="names" select="concat($newName,'+')" /> </xsl:apply-templates> </xsl:template> <xsl:template match="*" > <xsl:copy> <xsl:apply-templates select="map" /> </xsl:copy> </xsl:template> <xsl:template match="/*/map"> <xsl:apply-templates select="map" mode="concat"> <xsl:with-param name ="names" select="concat(@name,'+')" /> </xsl:apply-templates> </xsl:template> </xsl:stylesheet> 在这个小例子中,模式我不是必需的,但如果xlst文件增长则会有用. <?xml version="1.0"?> <system> <map name="Map+Map1"> <color>Map1 is red colored</color> <shape>Map1 is square shaped</shape> </map> <map name="Map+Map2"> <color>Map2 is green colored</color> </map> <map name="Map+Map2+Tap1"> <color>Tap1 is yellow colored</color> <speed>Tap1 is very fast</speed> </map> <map name="Map+Map2+Tap2"> <speed>Tap2 is very slow</speed> </map> </system> (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |