xml – 如何将此文件转换为yml？

发布时间：2020-12-16 22:39:08 所属栏目：百科来源：网络整理

导读：如何将此文件转换为yml？ container xmlns="http://symfony.com/schema/dic/services" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://symfony.com/schema/dic/services http://symfony.com/schema/dic/services/servic

如何将此文件转换为yml？

<container xmlns="http://symfony.com/schema/dic/services"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:schemaLocation="http://symfony.com/schema/dic/services http://symfony.com/schema/dic/services/services-1.0.xsd">
        <services>
           <service id="sonata.admin.course" class="YourNSAdminBundleAdminBlogAdmin">
              <tag name="sonata.admin" manager_type="orm" group="Posts" label="Blog"/>
              <argument />
              <argument>YourNSAdminBundleEntityCourse</argument>
              <argument>SonataAdminBundle:CRUD</argument>
              <call method="setTranslationDomain">
                  <argument>YourNSAdminBundle</argument>
              </call>
          </service>
       </services>
    </container>

解决方法

像这样的东西(我没试过)：

services:
  sonata.admin.course:
    class: YourNSAdminBundleAdminBlogAdmin
    arguments: [null,YourNSAdminBundleEntityCourse,'SonataAdminBundle:CRUD']
    calls:
        - [setTranslationDomain,YourNSAdminBundle]
    tags:
        - { name: sonata.admin,manager_type: orm,group: Posts,label: Blog }

（编辑：李大同）

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