无法找到用于XML模式命名空间的Spring NamespaceHandler [http:/
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我正在开发我的第一个应用程序在Spring的安全。我的applicationContext-security.xml文件看起来像这样:
<?xml version="1.0" encoding="UTF-8"?>
<!--
- Namespace-based OpenID configuration
-->
<b:beans xmlns="http://www.springframework.org/schema/security"
xmlns:b="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd">
<http>
<intercept-url pattern="/**" access="ROLE_USER"/>
<intercept-url pattern="/index.xhtml*" filters="none"/>
<logout/>
<openid-login login-page="/index.xhtml" authentication-failure-url="/index.xhtml?login_error=true">
<attribute-exchange>
<openid-attribute name="email" type="http://schema.openid.net/contact/email" required="true" count="2"/>
<openid-attribute name="name" type="http://schema.openid.net/namePerson/friendly" />
</attribute-exchange>
</openid-login>
<remember-me token-repository-ref="tokenRepo"/>
</http>
<b:bean id="tokenRepo"
class="org.springframework.security.web.authentication.rememberme.InMemoryTokenRepositoryImpl" />
<authentication-manager alias="authenticationManager"/>
<user-service id="userService">
<user name="http://user.myopenid.com/" authorities="ROLE_SUPERVISOR,ROLE_USER" />
</user-service>
</b:beans>
和Web.xml文件是: <?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
<display-name>Spring Security OpenID Demo Application</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/applicationContext-security.xml
</param-value>
</context-param>
<context-param>
<param-name>log4jConfigLocation</param-name>
<param-value>/WEB-INF/classes/log4j.properties</param-value>
</context-param>
<context-param>
<param-name>webAppRootKey</param-name>
<param-value>openid.root</param-value>
</context-param>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>faces/index.xhtml</welcome-file>
</welcome-file-list>
</web-app>
Clean和Build的应用程序是成功的,但当我尝试部署应用程序jetty 7给我以下错误:
试过一切,但不能解决这个错误。任何帮助将不胜感激。 编辑
你需要一个spring-security-config.jar在你的类路径。
异常意味着security:xml namescape不能被spring的“解析器”处理。它们是NamespaceHandler接口的实现,因此您需要一个知道如何处理< security:tags的处理程序。这是SecurityNamespaceHandler位于spring-security-config (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
