Ruby程序中发送基于HTTP协议的请求的简单示例

require "open-uri"  
#如果有GET请求参数直接写在URI地址中  
uri = 'http://uri'  
html_response = nil  
open(uri) do |http|  
html_response = http.read  
end  
puts html_response  
require "open-uri" 
#如果有GET请求参数直接写在URI地址中 
uri = 'http://uri' 
html_response = nil 
open(uri) do |http| 
html_response = http.read 
end 
puts html_response 

params = {}  
params["name"] = 'Tom'  
uri = URI.parse("http://uri")  
res = Net::HTTP.post_form
(uri,params)  
#返回的cookie  
puts res.header['set-cookie']  
#返回的html body  
puts res.body  
params = {} 
params["name"] = 'Tom' 
uri = URI.parse("http://uri") 
res = Net::HTTP.post_form
(uri,params)  
#返回的cookie 
puts res.header['set-cookie'] 
#返回的html body 
puts res.body 

# 
# 描述： 
#  发送快递数据到datasystem,使用https 
# 输入： 
#  data  - 组装后的expess的数据 
# 输出： 
#  datasystem返回的状态信息 
# 
def self.senddatassl(url,data) 
 url = url + data 
 $logger.info(url) 
 begin 
  uri = URI.parse(URI.escape(url)) 
  http = Net::HTTP.new(uri.host,uri.port) 
  http.use_ssl = true 
   
  if ($logger != nil) 
   $logger.info("链接地址参数:#{URI.escape(url)},文件名：#{__FILE__},第 #{__LINE__} 行") 
   $logger.info("传入data参数:#{data.to_json},第 #{__LINE__} 行") 
  end 
  request = Net::HTTP::Get.new(uri.request_uri) 
   
  response = http.request(request) 
 rescue =>exception 
  $logger.error("传递url地址为#{url}，错误!#{exception.to_s},第 #{__LINE__} 行") 
  return nil 
 end 
 return response.body 
end