在独立(不是rails)的ruby应用程序中使用slim或haml来指定布局和
发布时间:2020-12-16 22:13:42 所属栏目:百科 来源:网络整理
导读:我想在独立(不是rails)的应用程序中做这样的事情: layout.slim: h1 Hello.content = yield show.slim: = object.name= object.description 我不知道如何指定布局和模板.这是可能与苗条(或哈姆尔)吗?谢谢. 解决方法 layout.slim文件如下所示: h1 Hello.c
我想在独立(不是rails)的应用程序中做这样的事情:
layout.slim: h1 Hello .content = yield show.slim: = object.name = object.description 我不知道如何指定布局和模板.这是可能与苗条(或哈姆尔)吗?谢谢. 解决方法
layout.slim文件如下所示:
h1 Hello .content == yield contents.slim文件如下所示: = name 这可以缩短,但是为了解释目的,我分离到单独的步骤. require 'slim' # Simple class to represent an environment class Env attr_accessor :name end # Intialize it env = Env.new # Set the variable we reference in contents.slim env.name = "test this layout" # Read the layout file in as a string layout = File.open("layout.slim","rb").read # Read the contents file in as a string contents = File.open("contents.slim","rb").read # Create new template object with the layout l = Slim::Template.new { layout } # Render the contents passing in the environment: env # so that it can resolve: = name c = Slim::Template.new { contents }.render(env) # Render the layout passing it the rendered contents # as the block. This is what yield in layout.slim will get puts l.render{ c } 这将输出: <h1>Hello</h1><div class="content">test this layout</div> (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |