用Ruby测量两个字符串之间的距离?
发布时间:2020-12-16 20:28:33 所属栏目:百科 来源:网络整理
导读:我可以用Ruby测量两个字符串之间的距离吗? 即: compare('Test','est') # Returns 1compare('Test','Tes') # Returns 1compare('Test','Tast') # Returns 1compare('Test','Taste') # Returns 2compare('Test','tazT') # Returns 5 解决方法 我找到了你: d
我可以用Ruby测量两个字符串之间的距离吗? 即: compare('Test','est') # Returns 1 compare('Test','Tes') # Returns 1 compare('Test','Tast') # Returns 1 compare('Test','Taste') # Returns 2 compare('Test','tazT') # Returns 5 解决方法
我找到了你:
def levenshtein_distance(s,t) m = s.length n = t.length return m if n == 0 return n if m == 0 d = Array.new(m+1) {Array.new(n+1)} (0..m).each {|i| d[i][0] = i} (0..n).each {|j| d[0][j] = j} (1..n).each do |j| (1..m).each do |i| d[i][j] = if s[i-1] == t[j-1] # adjust index into string d[i-1][j-1] # no operation required else [ d[i-1][j]+1,# deletion d[i][j-1]+1,# insertion d[i-1][j-1]+1,# substitution ].min end end end d[m][n] end [ ['fire','water'],['amazing','horse'],["bamerindos","giromba"] ].each do |s,t| puts "levenshtein_distance('#{s}','#{t}') = #{levenshtein_distance(s,t)}" end 这是令人敬畏的输出:=) levenshtein_distance('fire','water') = 4 levenshtein_distance('amazing','horse') = 7 levenshtein_distance('bamerindos','giromba') = 9 资料来源:http://rosettacode.org/wiki/Levenshtein_distance#Ruby (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |