如何从没有特定名称的JSONObject获取String
发布时间:2020-12-16 19:52:59 所属栏目:百科 来源:网络整理
导读:请检查此代码示例. HttpEntity getResponseEntity = getResponse.getEntity();String message = EntityUtils.toString(getResponseEntity,"UTF-8");//message = {"EntryPointJsonResult":"{"NextTransactionUrl":null,"TraceId":null,"IsAuthorizationR
请检查此代码示例.
HttpEntity getResponseEntity = getResponse.getEntity(); String message = EntityUtils.toString(getResponseEntity,"UTF-8"); //message = {"EntryPointJsonResult":"{"NextTransactionUrl":null,"TraceId":null,"IsAuthorizationRequired":false,"IsError":false,"ErrorCode":null,"ErrorMessage":null}"} JSONObject object = new JSONObject(message); String objectString = object.getString("EntryPointJsonResult"); //objectString = {"NextTransactionUrl":null,"ErrorMessage":null} 这就是问题:我希望得到没有“EntryPointJsonResult”的“objectString”.导致此信息在另一个响应中有所不同. 那么如何在没有像“EntryPointJsonResult”这样的特定键的情况下获取“objectString”
你可以在不知道密钥的情况下获得这样的json对象的值
Iterator<String> keys= object.keys(); while (keys.hasNext()) { String keyValue = (String)keys.next(); String valueString = object.getString(keyValue); } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |