JSON.NET 简单的使用
JSON.NET(http://json.codeplex.com/)使用来将.NET中的对象转换为JSON字符串(序列化?),或者将JSON字符串转换为.NET中已有类型的对象(反序列化?) 首先为了例子随便定义一个类型: public class Product { public string Name { get; set; } public DateTime Expiry { get; set; } public decimal Price { get; set; } public string[] Sizes { get; set; } public override string ToString() { return string.Format("Name:{0},Expiry:{1},Price:{2},SizesCount:{3}",Name,Expiry,Price,Sizes.Length); } } 初始化对象: public static void Main(string[] passwordargs) { Product product = new Product() { Name = "android",Expiry = DateTime.Now,Price = 2000,Sizes = new string[] { "1.5","2.2","4.1" } }; } 进行到JSON的转换: Console.WriteLine(JsonConvert.SerializeObject(product)); 输出结果: {"Name":"android","Expiry":"2013-08-30T09:50:11.5147845+08:00","Price":2000.0,"Sizes":["1.5","4.1"]} 其它看起来一切正常,除了这个日期有点怪 格式化日期: //设置日期时间的格式,与DataTime类型的ToString格式相同 IsoDateTimeConverter iso = new IsoDateTimeConverter(); iso.DateTimeFormat = "yyyy-MM-dd HH:mm:ss"; Console.WriteLine(JsonConvert.SerializeObject(product,iso)); 输出结果: {"Name":"android","Expiry":"2013-08-30 09:53:58","4.1"]} 从JSON到对象的转换: string str = "{"Name":"android","Expiry":"2013-08-30 09:53:58","Price":2000.0,"Sizes":["1.5","2.2","4.1"]}"; Product p = (Product)JsonConvert.DeserializeObject(str,typeof(Product)); Console.WriteLine(p.ToString()); 输出结果: Name:android,Expiry:2013/8/30 9:53:58,Price:2000.0,SizesCount:3 从JSON到键值对的转换: string strJson = @"{""Name1"": ""小明"",""Name2"": ""小花"",""Name3"": ""小红""}"; Dictionary<string,string> _dictionary = JsonConvert.DeserializeObject<Dictionary<string,string>>(strJson); foreach (KeyValuePair<string,string> kp in _dictionary) { Console.WriteLine(kp.Key + ":" + kp.Value); } 输出结果: Name1:小明 从字符串转换到JSON对象,以及JSON对象的简单使用: string strJson2 = @"{ ""student"": { ""Name1"": ""小明"",""Name3"": ""小红""} }"; JObject jsonObj = JObject.Parse(strJson2); Console.WriteLine(jsonObj["student"]["Name1"].ToString()); Console.WriteLine(jsonObj["student"]["Name2"].ToString()); Console.WriteLine(jsonObj["student"]["Name3"].ToString()); 输出结果: 小明 直接生成JSON对象: JObject json = new JObject( new JProperty("Channel",new JObject( new JProperty("title","JSON"),new JProperty("link","JSON.NET"),new JProperty("description","JSON.NET Description"),new JProperty("items",new JArray( new JObject(new JProperty("haha1","123")),new JObject(new JProperty("haha2","456")),new JObject(new JProperty("haha3","789")) ))))); Console.WriteLine(json.ToString()); 输出结果: { 暂时先记录这么多,以后再继续补充 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |