Failed to load resource: the server responded with a status of 500 (Internal Server Error) ,
public String ajaxgetname() { System.out.println("ajaxgetname------------id:" +ajaxid); Staff s=staffService.getOneStaff(ajaxid); HttpServletResponse res = ServletActionContext.getResponse(); PrintWriter out = null; try { out = res.getWriter(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } System.out.println("ajax取得名字:jsonobject前"+s.getName()); //这里能执行到 JSONObject json = new JSONObject(); json=JSONObject.fromObject(s); System.out.println("发送的json:"+json.toString()); //这句输出不了 out.print(json); out.flush(); if(null != out){ out.close();//如果不关闭的话,ajax的回调函数不会调用 } return SUCCESS; }
我会怎么解决呢? (编辑:李大同)
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