1. JSON.parse(jsonString): 在一个字符串中解析出JSON对象
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var?
str =?
‘[{"href":"baidu.com","text":"test","orgId":123,"dataType":"curry","activeClass":"haha"}]‘
;
?
JSON.parse(str);
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结果：
2. JSON.stringify(obj) : 将一个JSON对象转换成字符串
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var?
obj = [{
"href"
:
"baidu.com"
,
"text"
:
"test"
,
"orgId"
:123,
"dataType"
:
"curry"
,
"activeClass"
:
"haha"
}];
?
JSON.stringify(obj);
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结果：
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1
|
"[{"
href
":"
baidu.com
","
text
":"
test
","
orgId
":123,"
dataType
":"
curry
","
activeClass
":"
haha
"}]"
|
3. jQuery.parseJSON(jsonString) : 将格式完好的JSON字符串转为与之对应的JavaScript对象?
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var?
str =?
‘[{"href":"baidu.com","activeClass":"haha"}]‘
;
?
jQuery.parseJSON(str);
|
结果：
4.JSON.parse()和jQuery.parseJSON()的区别：
有的浏览器不支持JSON.parse()方法，使用jQuery.parseJSON()方法时，在浏览器支持时会返回执行JSON.parse()方法的结果，否则会返回类似执行eval()方法的结果，以上结论参考jquery 1.9.1 得出：
?
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parseJSON:?
function
( data ) {
????
// Attempt to parse using the native JSON parser first
????
if?
( window.JSON && window.JSON.parse ) {
????????
return?
window.JSON.parse( data );
????
}
?
?
????
if?
( data ===?
null?
) {
????????
return?
data;
????
}
?
?
????
if?
(?
typeof?
data ===?
"string"?
) {
?
?
????????
// Make sure leading/trailing whitespace is removed (IE can‘t handle it)
????????
data = jQuery.trim( data );
?
?
????????
if?
( data ) {
????????????
// Make sure the incoming data is actual JSON
????????????
// Logic borrowed from http://json.org/json2.js
????????????
if?
( rvalidchars.test( data.replace( rvalidescape,?
"@"?
)
????????????????
.replace( rvalidtokens,?
"]"?
)
????????????????
.replace( rvalidbraces,?
""
)) ) {
?
?
????????????????
return?
(?
new?
Function(?
"return "?
+ data ) )();
????????????
}
????????
}
????
}
?
?
????
jQuery.error(?
"Invalid JSON: "?
+ data );
},
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