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SDNU 1382.Problem C: WERTYU(水题)

发布时间:2020-12-16 10:48:56 所属栏目:百科 来源:网络整理
导读:Description ? Problem C: WERTYU A common typing error is to place the hands on the keyboard one row to the right of the correct position. So "Q" is typed as "W" and "J" is typed as "K" and so on. You are to decode a message typed in this m

Description

?

Problem C: WERTYU

A common typing error is to place the hands on the keyboard one row to the right of the correct position. So "Q" is typed as "W" and "J" is typed as "K" and so on. You are to decode a message typed in this manner.

Input

Input consists of several lines of text. Each line may contain digits,spaces,upper case letters (except Q,A,Z),or punctuation shown above [except back-quote (`)]. Keys labelled with words [Tab,BackSp,Control, etc.] are not represented in the input.?

Output

You are to replace each letter or punctuation symbol by the one immediately to its left on the QWERTY keyboard shown above. Spaces in the input should be echoed in the output.

Sample Input

O S,GOMR YPFSU/

Sample Output

I AM FINE TODAY.

Source

Waterloo local 2001.01.27
#include <cstdio>
#include <iostream>
#include <cmath>
#include <string>
#include <cstring>
#include <algorithm>
#include <queue>
#include <vector>
#include <map>
using namespace std;
#define ll long long
const int inf = 0x3f3f3f3f;
const int mod = 1e9+7;

string s;

int main()
{
    while(getline(cin,s))
    {
        int len = s.size();
        for(int i = 0; i<len; i++)
        {
            if(s[i] == 1)printf("`");
            else if(s[i] == 2)printf("1");
            else if(s[i] == 3)printf("2");
            else if(s[i] == 4)printf("3");
            else if(s[i] == 5)printf("4");
            else if(s[i] == 6)printf("5");
            else if(s[i] == 7)printf("6");
            else if(s[i] == 8)printf("7");
            else if(s[i] == 9)printf("8");
            else if(s[i] == 0)printf("9");
            else if(s[i] == -)printf("0");
            else if(s[i] == =)printf("-");
            else if(s[i] == W)printf("Q");
            else if(s[i] == E)printf("W");
            else if(s[i] == R)printf("E");
            else if(s[i] == T)printf("R");
            else if(s[i] == Y)printf("T");
            else if(s[i] == U)printf("Y");
            else if(s[i] == I)printf("U");
            else if(s[i] == O)printf("I");
            else if(s[i] == P)printf("O");
            else if(s[i] == [)printf("P");
            else if(s[i] == ])printf("[");
            else if(s[i] == 92)printf("]");///
            else if(s[i] == S)printf("A");
            else if(s[i] == D)printf("S");
            else if(s[i] == F)printf("D");
            else if(s[i] == G)printf("F");
            else if(s[i] == H)printf("G");
            else if(s[i] == J)printf("H");
            else if(s[i] == K)printf("J");
            else if(s[i] == L)printf("K");
            else if(s[i] == ;)printf("L");
            else if(s[i] == 39)printf(";");
            else if(s[i] == X)printf("Z");
            else if(s[i] == C)printf("X");
            else if(s[i] == V)printf("C");
            else if(s[i] == B)printf("V");
            else if(s[i] == N)printf("B");
            else if(s[i] == M)printf("N");
            else if(s[i] == ,)printf("M");
            else if(s[i] == .)printf(",");
            else if(s[i] == /)printf(".");
            else if(s[i] ==  )printf(" ");
        }
        printf("n");
    }
    return 0;
}

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