标准C 11是否保证在函数调用之前创建传递给函数的临时对象？

即使临时对象传递为：

>对象
> rvalue-reference
>仅传递临时对象的成员

http://ideone.com/EV0hSP

#include <iostream>
using namespace std;

struct T { 
    T() { std::cout << "T created n"; }
    int val = 0;
    ~T() { std::cout << "T destroyed n"; }
};

void function(T t_obj,T &&t,int &&val) {
    std::cout << "func-start n";
    std::cout << t_obj.val << "," << t.val << "," << val << std::endl;
    std::cout << "func-end n";
}

int main() {

    function(T(),T(),T().val);

    return 0;
}

输出：

T created 
T created 
T created 
func-start 
0,0
func-end 
T destroyed 
T destroyed 
T destroyed

工作草案,编程语言标准C 2016-07-12：http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2016/n4606.pdf

§ 5.2.2 Function call

§ 5.2.2

1 A function call is a postfix
expression followed by parentheses containing a possibly empty,
comma-separated list of initializer-clauses which constitute the
arguments to the function.

但是可以在func-start之后创建T中的任何一个吗？

或者有没有办法将参数作为g / r / l / x / pr-value传递,以便在创建临时对象之前启动函数？