加入收藏 | 设为首页 | 会员中心 | 我要投稿 李大同 (https://www.lidatong.com.cn/)- 科技、建站、经验、云计算、5G、大数据,站长网!
当前位置: 首页 > 百科 > 正文

c – 如何使用互斥锁严格交替使用两个线程?

发布时间:2020-12-16 10:20:32 所属栏目:百科 来源:网络整理
导读:我需要创建两个严格交替的线程.这是我使用的示例代码: #include Windows.h#include iostreamusing std::cout;using std::endl;HANDLE g_hMutex1;HANDLE g_hMutex2;DWORD WINAPI ThreadFunc1(LPVOID lpParam);DWORD WINAPI ThreadFunc2(LPVOID lpParam);int
我需要创建两个严格交替的线程.这是我使用的示例代码:

#include <Windows.h>
#include <iostream>
using std::cout;
using std::endl;

HANDLE g_hMutex1;
HANDLE g_hMutex2;

DWORD WINAPI ThreadFunc1(LPVOID lpParam);
DWORD WINAPI ThreadFunc2(LPVOID lpParam);

int main(void)
{
    int nCalcNumber = 10;
    DWORD dwThreadId;
    HANDLE pThreadHandles[2];

    g_hMutex1 = CreateMutex(NULL,FALSE,NULL);
    g_hMutex1 = CreateMutex(NULL,NULL);

    pThreadHandles[0] = CreateThread(
        NULL,ThreadFunc1,static_cast<void*>(&nCalcNumber),&dwThreadId);

    pThreadHandles[1] = CreateThread(
        NULL,ThreadFunc2,&dwThreadId);

    WaitForMultipleObjects(2,pThreadHandles,TRUE,INFINITE);

    CloseHandle(pThreadHandles[0]);
    CloseHandle(pThreadHandles[1]);
    CloseHandle(g_hMutex1);
    CloseHandle(g_hMutex2);

    return 0;
}

DWORD WINAPI ThreadFunc1(LPVOID lpParam)
{
    int* nCalcNumber = static_cast<int*>(lpParam);

    for (int i = 0; i < *nCalcNumber; i++)
    {
        WaitForSingleObject(g_hMutex1,INFINITE);

        cout << "Func 1" << endl;

        ReleaseMutex(g_hMutex1);
    }

    return 0;
}

DWORD WINAPI ThreadFunc2(LPVOID lpParam)
{
    int* nCalcNumber = static_cast<int*>(lpParam);

    for (int i = 0; i < *nCalcNumber; i++)
    {
        WaitForSingleObject(g_hMutex1,INFINITE);

        cout << "Func 2" << endl;

        ReleaseMutex(g_hMutex1);
    }

    return 0;
}

结果,我希望收到:

Func 1
 Func 2
 Func 1
 Func 2
 Func 1
 Func 2
 ...and so one

应该添加什么来获得所需的结果.我可以使用第二个互斥锁吗?

解决方法

如果你可以使用信号量:你可以使用信号量而不是互斥量,它很容易使用相同的互斥量.

这段代码工作正常:

#include <windows.h>
#include <iostream>
using std::cout;
using std::endl;

PHANDLE sem1;
PHANDLE sem2;

DWORD WINAPI ThreadFunc1(LPVOID lpParam);
DWORD WINAPI ThreadFunc2(LPVOID lpParam);

int main(void)
{
    int nCalcNumber = 10;
    DWORD dwThreadId;
    HANDLE pThreadHandles[2];

    sem1 = (PHANDLE) CreateSemaphore(NULL,1,NULL);
    sem2 = (PHANDLE) CreateSemaphore(NULL,NULL);


    pThreadHandles[0] = CreateThread(
                                     NULL,static_cast<void*> (&nCalcNumber),&dwThreadId);

    pThreadHandles[1] = CreateThread(
                                     NULL,INFINITE);

    CloseHandle(pThreadHandles[0]);
    CloseHandle(pThreadHandles[1]);
    CloseHandle(sem1);
    CloseHandle(sem2);

    return 0;
}

DWORD WINAPI ThreadFunc1(LPVOID lpParam)
{
    int* nCalcNumber = static_cast<int*> (lpParam);

    for (int i = 0; i < *nCalcNumber; i++)
    {
        WaitForSingleObject(sem1,INFINITE);

        cout << "Func 1" << endl;

        ReleaseSemaphore(sem2,NULL);
    }

    return 0;
}

DWORD WINAPI ThreadFunc2(LPVOID lpParam)
{
    int* nCalcNumber = static_cast<int*> (lpParam);

    for (int i = 0; i < *nCalcNumber; i++)
    {

        WaitForSingleObject(sem2,INFINITE);

        cout << "Func 2" << endl;

        ReleaseSemaphore(sem1,NULL);
    }

    return 0;
}

(编辑:李大同)

【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容!

    推荐文章
      热点阅读