C列表实施

发布时间：2020-12-16 10:18:28 所属栏目：百科来源：网络整理

导读：所以,我正在为编程练习构建List的实现.到目前为止我有这个： #include iostream #include algorithmusing namespace std;template class T class Link;template class T class List_iterator;template class T class List{public: typedef List_iteratorT it

所以,我正在为编程练习构建List的实现.到目前为止我有这个：

#include <iostream> 
#include <algorithm>

using namespace std;

template <class T> class Link;
template <class T> class List_iterator;

template <class T> 
class List
{
public:
   typedef List_iterator<T> iterator;

   List();
   List(const List<T> & l);
   ~List();

   bool empty() const;
   unsigned int size() const; 
   T & back() const;
   T & front() const;
   void push_front(const T & x);
   void push_back(const T & x);
   void pop_front();
   void pop_back();
   iterator begin() const;
   iterator end() const;
   void insert(iterator pos,const T & x);
   void erase(iterator & pos); 
   List<T> & operator=(const List<T> & l);

protected:
   Link<T> * first_link;
   Link<T> * last_link;
   unsigned int my_size;
};

template <class T>
List<T>::List()
{
        first_link = 0;
        last_link = 0;
        my_size = 0;
}

template <class T>
List<T>::List(const List & l)
{
        first_link = 0;
        last_link = 0;
        my_size = 0;
        for (Link<T> * current = l.first_link; current != 0; current = current -> next_link)
                push_back(current -> value);
}

template <class T>
typename List<T>::iterator List<T>::begin() const
{
        return iterator(first_link);
}

template <class T> 
class Link 
{
private:
   Link(const T & x): value(x),next_link(0),prev_link(0) {}//pg. 204 

   T value;     
   Link<T> * next_link;
   Link<T> * prev_link;

   friend class List<T>;
   friend class List_iterator<T>;
};

template <class T> class List_iterator
{
public:
   typedef List_iterator<T> iterator;

   List_iterator(Link<T> * source_link): current_link(source_link) { }
   List_iterator(): current_link(0) { }
   List_iterator(List_iterator<T> * source_iterator): current_link(source_iterator.current_link) { }

   T & operator*();  // dereferencing operator
   iterator & operator=(const iterator & rhs);
   bool operator==(const iterator & rhs) const;
   bool operator!=(const iterator & rhs) const;
   iterator & operator++(); 
   iterator operator++(int);
   iterator & operator--(); 
   iterator operator--(int); 

protected:
   Link<T> * current_link;

   friend class List<T>;
};

template <class T>
T & List_iterator<T>::operator*()
{
        return current_link -> value;
}

template <class T>
List_iterator<T> & List_iterator<T>::operator++()
{
        current_link = current_link -> next_link;
        return *this;
}

template <class T>
void List<T>::push_back(const T & x)
{
    link<T> * last_link = new link<T> (x);
    if (empty())
    first_link = last_link;
    else 
    {
        last_link->prev_link = last_link;
        last_link->prev_link = last_link;
    last_link = last_link;
    }
}

template <class T>
typename List<T>::iterator List<T>::end() const
{
        return iterator(last_link);
}

int main()
{
   List<int> l;

   l.push_back(44);  // list = 44
   l.push_back(33);  // list = 44,33
   l.push_back(11);  // list = 44,33,11
   l.push_back(22);  // list = 44,11,22

   List<int> m(l);

   List<int>::iterator itr(m.begin());
   while (itr != m.end()) {
        cout << *itr << endl;
        itr++;
   }
}`

我的push_back()函数遇到了很多麻烦,我不太确定是什么问题.任何人都可以指出我的错误吗？

正在更新的代码：

#include <iostream> 
#include <algorithm>

using namespace std;

template <class T> class Link;
template <class T> class List_iterator;

template <class T> 
class List
{
public:
   typedef List_iterator<T> iterator;

   List();
   List(const List<T> & l);
   ~List();

   bool empty() const;
   unsigned int size() const; 
   T & back() const;
   T & front() const;
   void push_front(const T & x);
   void push_back(const T & x);
   void pop_front();
   void pop_back();
   iterator begin() const;
   iterator end() const;
   void insert(iterator pos,prev_link(0) {}//pg. 204 

   T value;     
   Link<T> * next_link;
   Link<T> * prev_link;

   friend class List<T>;
   friend class List_iterator<T>;
};

template <class T> class List_iterator//pg.207
{
public:
   typedef List_iterator<T> iterator;

   List_iterator(Link<T> * source_link): current_link(source_link) { }
   List_iterator(): current_link(0) { }
   List_iterator(List_iterator<T> * source_iterator): current_link(source_iterator.current_link) { }

   T & operator*();  // dereferencing operator
   iterator & operator=(const iterator & rhs);
   bool operator==(const iterator & rhs) const;
   bool operator!=(const iterator & rhs) const;
   iterator & operator++(); 
   iterator operator++(int);
   iterator & operator--(); 
   iterator operator--(int); 

protected:
   Link<T> * current_link;

   friend class List<T>;
};

template <class T>
T & List_iterator<T>::operator*()
{
        return current_link -> value;
}

template <class T>
List_iterator<T> & List_iterator<T>::operator++()
{
        current_link = current_link -> next_link;
        return *this;
}

template <class T>
void List<T>::push_back(const T & x)
{
    Link<T> * new_link = new Link<T> (x);
    if (first_link = 0)
    first_link = last_link = new_link;
    else
    {
    new_link->prev_link = last_link;
        last_link->next_link = new_link;    
        last_link = new_link;
    }
    my_size++;
}

template <class T>
typename List<T>::iterator List<T>::end() const
{
        return iterator(last_link);
}

template <class T>
List <T>::~List()
{
    Link <T> * first = first_link;
    while (first != 0)
    {
    Link <T> * next = first->next_link;
        delete first;
    first = next;
    }
}

template<class T>
bool List_iterator<T>::operator==(const iterator & rhs) const
{
    return ( this->current_link == rhs.current_link ); 
}

template <class T>
bool List_iterator<T>::operator!=(const iterator & rhs) const
{
    return !( *this == rhs );
}

int main()
{
   List<int> l;

   l.push_back(44);  // list = 44
   l.push_back(33);  // list = 44,22

   List<int> m(l);

   List<int>::iterator itr(m.begin());
   while (itr != m.end()) {
        cout << *itr << endl;
        ++itr;
   }
}

解决方法

马里奥和乔的答案都是有效的(如果可以,我会投票给他们).

问题1

假设你发布的是push_back()的ACTUAL代码,那么Link< T>有错误的情况.

link<T> * last_link = new link<T> (x);

…应该：

Link<T> * last_link = new Link<T> (x);

这样做可以消除错误：在’>’标记之前预期的primary-expression(当用g编译时)

问题2

Mario和Joe建议的替代方法是不要隐藏你的List< T>的last_link.使用与类的数据成员名称不同的临时变量.更改：

Link<T> * last_link = new Link<T> (x);

…至…

Link<T> * new_link = new Link<T> (x);

这将使您的代码更清晰,您将引用正确的节点.

问题3

按照上述步骤应该在push_back()中出现两个逻辑错误.我愿意帮助,但我相信你会看到它.

（编辑：李大同）

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