c – 无法将std :: string转换为日期类型
发布时间:2020-12-16 10:04:19 所属栏目:百科 来源:网络整理
导读:我使用 Howard Hinnant’s date library并尝试使用下面显示的代码将std :: string转换为date :: year_month_day. #include "date.h"#include string#include iostream#include sstreamint main(){ std::string d = "2016-11-23"; std::istringstream in{d};
我使用
Howard Hinnant’s date library并尝试使用下面显示的代码将std :: string转换为date :: year_month_day.
#include "date.h" #include <string> #include <iostream> #include <sstream> int main() { std::string d = "2016-11-23"; std::istringstream in{d}; date::sys_days sd; date::parse(in,"%F",sd); date::year_month_day ymd = sd; std::cout << ymd << 'n'; } 并且收到太多错误抱怨’const class std :: time_get< char>‘没有名为’get’的成员 In file included from convert_string_to_date.cpp:1:0: date.h: In instantiation of ‘void date::detail::parse(std::basic_istream<_CharT,_Traits>&,const std::basic_string<CharT,Traits>&,date::local_time<Duration>&,std::basic_string<CharT,Traits>*,std::chrono::minutes*) [with CharT = char; Traits = std::char_traits<char>; Duration = std::chrono::duration<int,std::ratio<86400l,1l> >; date::local_time<Duration> = std::chrono::time_point<date::local_t,std::chrono::duration<int,1l> > >; std::chrono::minutes = std::chrono::duration<long int,std::ratio<60l> >]’: date.h:4371:90: required from ‘void date::detail::parse(std::basic_istream<_CharT,std::ratio<60l> >]’ date.h:4447:42: required from ‘void date::parse(std::basic_istream<_CharT,date::sys_time<Duration>&) [with CharT = char; Traits = std::char_traits<char>; Duration = std::chrono::duration<int,1l> >; date::sys_time<Duration> = std::chrono::time_point<std::chrono::_V2::system_clock,1l> > >]’ date.h:4649:59: required from ‘void date::parse(std::basic_istream<_CharT,const CharT*,1l> > >]’ convert_string_to_date.cpp:12:27: required from here date.h:4192:21: error: ‘const class std::time_get<char>’ has no member named ‘get’ f.get(is,is,err,&tm,b,i-1); ^ date.h:4197:25: error: ‘const class std::time_get<char>’ has no member named ‘get’ f.get(is,ymd,ymd+8); ^ date.h:4211:21: error: ‘const class std::time_get<char>’ has no member named ‘get’ f.get(is,i-1); ^ date.h:4221:25: error: ‘const class std::time_get<char>’ has no member named ‘get’ f.get(is,hm,hm+6); ^ date.h:4266:25: error: ‘const class std::time_get<char>’ has no member named ‘get’ f.get(is,hm+2); ^ date.h:4275:21: error: ‘const class std::time_get<char>’ has no member named ‘get’ f.get(is,i-1-modified); ^ date.h:4322:21: error: ‘const class std::time_get<char>’ has no member named ‘get’ f.get(is,i-1); ^ date.h:4343:17: error: ‘const class std::time_get<char>’ has no member named ‘get’ f.get(is,e); 解决方法
gcc 4.9没有date.h所需的完整time_get支持.它适用于gcc 5.
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