将C lambdas存储为二进制数据

我得到的问题是,虽然存储和调用代码可以知道lambda的签名(这是设置将执行lambda的函数的代码)

// Arg Count 0
template <class R,class Args,class Arity>
SQFUNCTION SqMemberLambdaFuncDetail(R result,Args args,boost::mpl::integral_c<unsigned int,1> arity)
{
    return &SqLambda<R>::template Func0<false>;
}

// Arg Count 1
template <class R,2> arity)
{
    return &SqLambda<R>::template Func1<boost::mpl::at_c<Args,1>::type,2,false>;
}

template <class F>
SQFUNCTION SqMemberLambdaFunc(F f)
{
    typedef boost::function_types::result_type<decltype(&F::operator())>::type result_t;
    typedef boost::function_types::function_arity< decltype(&F::operator())> arity_t;
    typedef boost::function_types::parameter_types< decltype(&F::operator())>::type args_t;
    result_t result;
    args_t args;
    arity_t arity;
    return SqMemberLambdaFuncDetail<result_t,args_t,arity_t>(result,args,arity);
}

lambda本身需要以匿名形式存储,作为二进制数据,我似乎无法找到这样做的方法.