c – 删除使用new创建的2D或3D指针

// 1D pointer:
int *pt1 = new int[size];             // Creating 1D pointer
delete [] pt1;                        // Deleting 1D pointer


// 3D pointer   L: # of layers,R: # of rows,C: # of columns
int (*pt2)[L][R][C] = new int[1][L][R][C];   // L:2,R:2,C:3 (ex. below)
delete [] pt2;

我使用它来创建和删除3D指针,但它只删除了指针pt2的前两个条目,无论我运行代码多少次,其余10个条目保持不变.

例如：

int B[2][2][3] = {{{0,1,2},{3,4,5}},{{6,7,8},{9,10,11}}};

int (*pb)[2][2][3] = new int[1][2][2][3];

for(int k=0; k<2; k++){
    for(int j=0; j<2; j++){
        for(int i=0; i<3; i++){
            *(*(*(*(pb)+k)+j)+i) = B[k][j][i];
            cout << "k,j,i: " << k << "," << j << "," << i;
            cout << " " << B[k][j][i] << " " << *(*(*(*(pb)+k)+j)+i) << endl;
        };
        cout << endl;
    };
    cout << endl;
};

delete [] pb;


for(int k=0; k<2; k++){
    for(int j=0; j<2; j++){
        for(int i=0; i<3; i++){
            cout << "k," << i;
            cout << " " << B[k][j][i] << " " << *(*(*(*(pb)+k)+j)+i) << endl;
        };
        cout << endl;
    };
    cout << endl;
};

我得到了(k,i)=(0,0)&的垃圾值. (0,1)对pb执行删除操作后,其余所有10个值保持不变.