C++/C++11中std::transform的使用
std::transform在指定的范围内应用于给定的操作,并将结果存储在指定的另一个范围内。要使用std::transform函数需要包含<algorithm>头文件。 以下是std::transform的两个声明,一个是对应于一元操作,一个是对应于二元操作: template <class InputIterator,class OutputIterator,1)">class UnaryOperation> OutputIterator transform (InputIterator first1,InputIterator last1,OutputIterator result,UnaryOperation op); template <class InputIterator1,1)">class InputIterator2,class BinaryOperation> OutputIterator transform (InputIterator1 first1,InputIterator1 last1,InputIterator2 first2,BinaryOperation binary_op); 对于一元操作,将op应用于[first1,last1)范围内的每个元素,并将每个操作返回的值存储在以result开头的范围内。给定的op将被连续调用last1-first1次。op可以是函数指针或函数对象或lambda表达式。 如op的一个实现 即将[first1,last1)范围内的每个元素加5,然后依次存储到result中。 int op_increase(int i) {return (i + 5)};
调用std::transform的方式如下: std::transform(first1,last1,result,op_increase);
对于二元操作,使用[first1,last1)范围内的每个元素作为第一个参数调用binary_op,并以first2开头的范围内的每个元素作为第二个参数调用binary_op,每次调用返回的值都存储在以result开头的范围内。给定的binary_op将被连续调用last1-first1次。binary_op可以是函数指针或函数对象或lambda表达式。 如binary_op的一个实现即将first1和first2开头的范围内的每个元素相加,然后依次存储到result中。 int op_add(int,a,1)">int b) {return (a + b)}; std::transform支持in place,即result和first1指向的位置可以是相同的。std::transform的主要作用应该就是省去了我们自己写for循环实现。 以下是摘自对std::transform的英文解释: /*
// reference: http://en.cppreference.com/w/cpp/algorithm/transform
template< class InputIt,class OutputIt,class UnaryOperation >
OutputIt transform( InputIt first1,InputIt last1,OutputIt d_first,UnaryOperation unary_op )
{
while (first1 != last1) {
*d_first++ = binary_op(*first1++,*first2++);
}
return d_first;
}
template< class InputIt1,class InputIt2,class BinaryOperation >
OutputIt transform( InputIt1 first1,InputIt1 last1,InputIt2 first2,BinaryOperation binary_op );
std::transform applies the given function to a range and stores the result in another range,beginning at d_first.
(1): The unary operation unary_op is applied to the range defined by [first1,last1).
(2): The binary operation binary_op is applied to pairs of elements from two ranges:
one defined by [first1,last1) and the other beginning at first2.
Parameters:
first1,last1: the first range of elements to transform
first2: the beginning of the second range of elements to transform
d_first:the beginning of the destination range,may be equal to first1 or first2
unary_op: unary operation function object that will be applied.
binary_op: binary operation function object that will be applied.
Return value: Output iterator to the element past the last element transformed.
std::for_each: ignores the return value of the function and guarantees order of execution.
std::transform: assigns the return value to the iterator,and does not guarantee the order of execution.
*/
以下是std::transform用法举例: #include "transform.hpp" #include <algorithm> // std::transform #include <string> #include <cctype> std::toupper #include <iostream> #include <vector> #include <functional> std::plus c++14 int test_transform1() { std::string s(Hello); std::transform(s.begin(),s.end(),s.begin(),[](unsigned char c) { return std::toupper(c); }); std::cout << s << std::endl; HELLO std::transform(s.begin(),::tolower); std::cout << s << std::endl; hello //////////////////////////////// std::vector<int> arr{ 1,3,1)">5 }; std::vector<int> arr2{ int> arr3{ }; std::transform(arr.begin(),arr.end(),arr.begin(),[](int d) -> int {return d * 5; }); for_each for (auto value : arr) { std::cout << value << " "; 5 15 25 } std::cout<<std::endl; std::for_each(arr2.begin(),arr2.end(),1)">int& a) {a *= ; }); (auto value : arr2) { std::cout << value << } std::cout << std::endl; for (auto& value : arr3) { value *= ; } (auto value : arr3) { std::cout << value << std::endl; std::vector<std::string> names = { hi",1)">testfoo }; std::vector<std::size_t> name_sizes; /////////////////////////// std::transform(names.begin(),names.end(),std::back_inserter(name_sizes),[](std::string name) { name.size(); }); (auto value : name_sizes) { std::cout << value << 2 4 3 std::endl; std::for_each(name_sizes.begin(),name_sizes.end(),[](std::size_t name_size) { std::cout << name_size << }); std::cout <<return 0; } ///////////////////////////////////////////////////////// reference: http://www.cplusplus.com/reference/algorithm/transform/ static int i) { return ++i; } test_transform2() { std::vector<int> foo; std::vector< bar; set some values: for (int i = 1; i<6; i++) foo.push_back(i * 10); foo: 10 20 30 40 50 bar.resize(foo.size()); allocate space std::transform(foo.begin(),foo.end(),bar.begin(),op_increase); bar: 11 21 31 41 51 std::plus adds together its two arguments: std::transform(foo.begin(),foo.begin(),std::plus<()); foo: 21 41 61 81 101 std::cout << foo contains:; for (std::vector<int>::iterator it = foo.begin(); it != foo.end(); ++it) std::cout << ' ' << *it; 21 41 61 81 101 std::cout << 'n'; ; } ? ? (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |