一.在工程目录下，新建txt文件取名Skills，修改其属性运行时复制到工作目录中；
右键选择Open with
选择Xml方便编辑txt内容
二.新建一个SkillInfo类，用来存储Skill信息
class SkillInfo
{
public int ID { get; set; }
public string Name { get; set; }
public int Damage { set; get; }
public string Language { get; set; }
public override string ToString()
{
return string.Format("ID:" + ID + ",Name:" + Name + ",Damage:" + Damage + ",Language:" + Language);
}
}
static void Main(string[] args)
{
List<SkillInfo> SkillList = new List<SkillInfo>();
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load("Skills.txt");
XmlNode skills = xmlDoc.FirstChild;
XmlNodeList skillList = skills.ChildNodes;
foreach (XmlNode skill in skillList)
{
XmlNodeList skillInfo = skill.ChildNodes;
SkillInfo skillObject = new SkillInfo();
foreach (XmlNode info in skillInfo)
{
if (info.Name== "ID")
{
skillObject.ID =int.Parse(info.InnerText);
}
if (info.Name == "Name")
{
skillObject.Name = info.InnerText;
skillObject.Language = info.Attributes[0].Value;
}
if (info.Name == "Damage")
{
skillObject.Damage = int.Parse(info.InnerText);
}
}
SkillList.Add(skillObject);
}
foreach(SkillInfo list in SkillList)
{
Console.WriteLine(list.ToString());
}
Console.ReadKey();
}
Skills.txt文本编写格式如下：
结果如下：
（编辑：李大同）
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